blocks|key|75436|text|您可以使用LINQ的Distinct()方法，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|75437|myList+=+myList.Distinct().ToList();|code-block|syntax|javascript|75438|请注意，这将重新创建列表，而不是在适当的位置删除重复项。|75439|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.linq.enumerable.distinct.aspx^0|A|A|A|A|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|11|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

You can use <a href="http://msdn.microsoft.com/en-us/library/system.linq.enumerable.distinct.aspx"><code>Distinct()</code></a> method of LINQ, like this:

<pre><code>myList = myList.Distinct().ToList();
</code></pre>

Note that this would re-create the list, rather than removing the duplicates in place.

blocks|key|75457|text|使用distinct()方法：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|75458|myList.Distinct().ToList();|code-block|syntax|javascript|75459|entityMap^0|2|A|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use <code>distinct()</code> method:

<pre><code>myList.Distinct().ToList();
</code></pre>

blocks|key|292667|text|如果您想要一个适当的解决方案来修正列表，您可以使用HashSet<T>+(或者对于较旧的框架，使用Dictionary<Tuple<string,+string>,+object>并忽略该值)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|292668|var+existing+=+new+HashSet<Tuple<string,+string>>();

for+(int+i+=+myList.Count+-+1;+i+>=+0;+i--)
{
++++if+(existing.Contains(myList[i]))
++++{
++++++++myList.RemoveAt(i);
++++}
++++else
++++{
++++++++existing.Add(myList[i]);
++++}
}|code-block|syntax|javascript|292669|我们在不使用迭代器的情况下向后计数(否则在迭代时修改列表会出错)。|292670|如果你需要的话，HashSet<T>也有重载来重写相等。|292671|就我个人而言，为了可读性，我倾向于使用dasblinkenlight's+answer。|292672|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/17275763/358221^0|P|A|1D|15|0|0|0|8|A|0|J|O|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|18|8|@]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|Q|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

If you want a solution that amends the list in place, you can make use of a <code>HashSet&lt;T&gt;</code> (or for older frameworks a <code>Dictionary&lt;Tuple&lt;string, string&gt;, object&gt;</code> and ignore the value):

<pre><code>var existing = new HashSet&lt;Tuple&lt;string, string&gt;&gt;();

for (int i = myList.Count - 1; i &gt;= 0; i--)
{
 if (existing.Contains(myList[i]))
 {
 myList.RemoveAt(i);
 }
 else
 {
 existing.Add(myList[i]);
 }
}
</code></pre>

We count backwards without using an iterator (otherwise you'd get errors amending the list while iterating).

<code>HashSet&lt;T&gt;</code> also has overloads for overriding equality should you need it.

Personally I'd go for <a href="https://stackoverflow.com/a/17275763/358221">dasblinkenlight's answer</a> for readability.

blocks|key|292690|text|您可以使用HashSet实现此目的(http://msdn.microsoft.com/en-us/library/bb359438.aspx)|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|292691|class+SameTuplesComparer<T1,+T2>+:+EqualityComparer<Tuple<T1,+T2>>+
{
+++public+override+bool+Equals(Tuple<T1,+T2>+t1,+Tuple<T1,+T2>+t2)
+++{
++++++return+t1.Item1.Equals(t2.Item1)+&&+t1.Item2.Equals(t2.Item2)
+++}


+++public+override+int+GetHashCode(Tuple<T1,+T2>+t)
+++{
+++++return+base.GetHashCode();
+++}
}|code-block|syntax|javascript|292692|因此，如果你编写自己的比较器，你可以用一些不同的方式比较字符串(例如，不是casesensetive)：|292693|class+SameStringTuplesComparer:+EqualityComparer<Tuple<string,+string>>+
{
+++public+override+bool+Equals(Tuple<string,+string>+t1,+Tuple<string,+string>+t2)
+++{
++++++return+t1.Item1.Equals(t2.Item1,+StringComparison.CurrentCultureIgnoreCase)+&&+t1.Item2.Equals(t2.Item2,+StringComparison.CurrentCultureIgnoreCase)
+++}


+++public+override+int+GetHashCode(Tuple<string,+string>+t)
+++{
+++++return+base.GetHashCode();
+++}
}|292694|然后在代码中：|292695|var+hashSet+=+new+HashSet<Tuple<string,+string>>(list,+new+SameTuplesComparer());|292696|或者没有你自己的比较器：|292697|var+hashSet+=+HashSet<Tuple<string,+string>>(list);|292698|现在您可以向hashSet添加元素，所有元素都将是唯一的。添加完元素后，您可以将其再次转换为list：|292699|var+uniquedList+=+hashSet.ToList();|292700|或者只使用list.Distinct().ToList()|style|CODE|292701|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/bb359438.aspx^0|I|1H|0|0|0|0|0|0|0|0|0|0|0|5|O|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@$A|1B|B|1C|1|1D]]|C|$]]|$1|D|3|E|5|F|7|1E|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|1F|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|1G|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|1H|8|@]|9|@]|C|$]]|$1|O|3|P|5|F|7|1I|8|@]|9|@]|C|$G|H]]|$1|Q|3|R|5|6|7|1J|8|@]|9|@]|C|$]]|$1|S|3|T|5|F|7|1K|8|@]|9|@]|C|$G|H]]|$1|U|3|V|5|6|7|1L|8|@]|9|@]|C|$]]|$1|W|3|X|5|F|7|1M|8|@]|9|@]|C|$G|H]]|$1|Y|3|Z|5|6|7|1N|8|@$A|1O|B|1P|10|11]]|9|@]|C|$]]|$1|12|3|-4|5|6|7|1Q|8|@]|9|@]|C|$]]]|13|$14|$5|15|16|17|C|$18|19]]]]

You can use HashSet for this purposes (<a href="http://msdn.microsoft.com/en-us/library/bb359438.aspx" rel="noreferrer">http://msdn.microsoft.com/en-us/library/bb359438.aspx</a>)

<pre><code>class SameTuplesComparer&lt;T1, T2&gt; : EqualityComparer&lt;Tuple&lt;T1, T2&gt;&gt; 
{
 public override bool Equals(Tuple&lt;T1, T2&gt; t1, Tuple&lt;T1, T2&gt; t2)
 {
 return t1.Item1.Equals(t2.Item1) &amp;&amp; t1.Item2.Equals(t2.Item2)
 }


 public override int GetHashCode(Tuple&lt;T1, T2&gt; t)
 {
 return base.GetHashCode();
 }
}
</code></pre>

So if you write your own comparer, you can compare strings a little differently (as example, not casesensetive):

<pre><code>class SameStringTuplesComparer: EqualityComparer&lt;Tuple&lt;string, string&gt;&gt; 
{
 public override bool Equals(Tuple&lt;string, string&gt; t1, Tuple&lt;string, string&gt; t2)
 {
 return t1.Item1.Equals(t2.Item1, StringComparison.CurrentCultureIgnoreCase) &amp;&amp; t1.Item2.Equals(t2.Item2, StringComparison.CurrentCultureIgnoreCase)
 }


 public override int GetHashCode(Tuple&lt;string, string&gt; t)
 {
 return base.GetHashCode();
 }
}
</code></pre>

Then in code:

<pre><code>var hashSet = new HashSet&lt;Tuple&lt;string, string&gt;&gt;(list, new SameTuplesComparer());
</code></pre>

Or without your own comparer:

<pre><code>var hashSet = HashSet&lt;Tuple&lt;string, string&gt;&gt;(list);
</code></pre>

Now you can add elements to hashSet and all elements will be unique. After you done with adding elements you can convert it to list again:

<pre><code>var uniquedList = hashSet.ToList();
</code></pre>

Or just use <code>list.Distinct().ToList()</code>

I need to find and remove the duplicates from a List of tuples.
Basically, my structure is made like that:

<pre><code>List&lt;Tuple&lt;string, string&gt;&gt; myList = new List&lt;Tuple&lt;string, string&gt;&gt;();

****

private void FillStructure()
{
 myList.Add(Tuple.Create&lt;string, string&gt;("A", "B"));
 myList.Add(Tuple.Create&lt;string, string&gt;("A", "C"));
 myList.Add(Tuple.Create&lt;string, string&gt;("C", "B"));
 myList.Add(Tuple.Create&lt;string, string&gt;("C", "B")); // Duplicate
 myList.Add(Tuple.Create&lt;string, string&gt;("A", "D"));

 FindAndRemoveDuplicates(myList);
}

private void FindAndRemoveDuplicates(List&lt;Tuple&lt;string, string&gt;&gt; myList)
{
 // how can I perform this ?
}
</code></pre>

I can't use a Dictionary because I can have the same key but different values!
Thank you in advance

Find and Deletes Duplicates in List of Tuples in C#

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要从元组列表中找到并删除重复项。基本上，我的结构是这样的：List<Tuple<string, string>> myList = new List<Tuple<string, string>>();****private void FillStructure(){ myList.Add(Tuple.Cre...

问在C#的元组列表中查找和删除重复项
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