blocks|key|1146191|text|您不能使用ActionLink，因为这只会呈现一个锚<a>标记。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1146192|您可以使用jQuery+AJAX+post。|1146193|或者只调用表单的submit方法，不管有没有jQuery+(这可能是非AJAX的)，也许在onclick事件中使用您喜欢的任何控件。|1146194|entityMap|0|LINK|mutability|MUTABLE|url|https://api.jquery.com/jQuery.post/^0|5|A|Q|3|0|5|G|0|0|19|7|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|H|3|I|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|K|$L|$5|M|N|O|E|$P|Q]]]]

<p>You can't use an <code>ActionLink</code> because that just renders an anchor <code>&lt;a&gt;</code> tag.<br>
You can use a <a href="https://api.jquery.com/jQuery.post/" rel="nofollow noreferrer">jQuery AJAX post</a>.<br>
Or just call the form's submit method with or without jQuery (which would be non-AJAX), perhaps in the <code>onclick</code> event of whatever control takes your fancy.</p>


blocks|key|1146332|text|如果你正在使用ASP，你可以使用Ajax.ActionLink()，它允许你指定一个你可以设置为"POST“的MVC3方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146333|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

<p>If you're using ASP MVC3 you could use an Ajax.ActionLink(), that allows you to specify a HTTP Method which you could set to "POST".</p>


blocks|key|1361660|text|你可以使用jQuery为你所有的按钮做一个POST。只需为它们提供相同的CssClass名称。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361661|如果你想在post之后做一个服务器端的RedirectToAction，那么在onclick+javascript事件的末尾使用"return+false;“，否则就返回视图。|1361662|Razor代码|1361663|@using+(Html.BeginForm())
{
++++@Html.HiddenFor(model+=>+model.ID)+
++++@Html.ActionLink("Save",+"SaveAction",+"MainController",+null,+new+{+@class+=+"saveButton",+onclick+=+"return+false;"+})
}|code-block|syntax|javascript|1361664|JQuery代码|1361665|$(document).ready(function+()+{
++++++++$('.saveButton').click(function+()+{
++++++++++++$(this).closest('form')[0].submit();
++++++++});
++++});|1361666|C#|1361667|[AcceptVerbs(HttpVerbs.Post)]
public+ActionResult+SaveAction(SaveViewModel+model)
{
++++//+Save+code+here...

++++return+RedirectToAction("Index");
++++//return+View(model);
}|1361668|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|Z|8|@]|9|@]|A|$I|J]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|H|7|11|8|@]|9|@]|A|$I|J]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

<p>You can use jQuery to do a POST for all your buttons. Just give them the same CssClass name.</p>

<p>Use "return false;" at the end of your onclick javascript event if you want to do a server side RedirectToAction after the post otherwise just return the view. </p>

<p>Razor Code</p>

<pre><code>@using (Html.BeginForm())
{
    @Html.HiddenFor(model =&gt; model.ID) 
    @Html.ActionLink("Save", "SaveAction", "MainController", null, new { @class = "saveButton", onclick = "return false;" })
}
</code></pre>

<p>JQuery Code</p>

<pre><code>$(document).ready(function () {
        $('.saveButton').click(function () {
            $(this).closest('form')[0].submit();
        });
    });
</code></pre>

<p>C#</p>

<pre><code>[AcceptVerbs(HttpVerbs.Post)]
public ActionResult SaveAction(SaveViewModel model)
{
    // Save code here...

    return RedirectToAction("Index");
    //return View(model);
}
</code></pre>


blocks|key|1361732|text|@Aidos有正确的答案，只是想弄清楚，因为它隐藏在@CodingWithSpike对他的帖子的评论中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361733|@Ajax.ActionLink("Delete",+"Delete",+new+{+id+=+item.ApkModelId+},+new+AjaxOptions+{+HttpMethod+=+"POST"+})|code-block|syntax|javascript|1361734|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>@Aidos had the right answer just wanted to make it clear since it is hidden inside a comment on his post made by @CodingWithSpike.</p>

<pre><code>@Ajax.ActionLink("Delete", "Delete", new { id = item.ApkModelId }, new AjaxOptions { HttpMethod = "POST" })
</code></pre>


blocks|key|1361932|text|这是默认的ASP.NET+MVC5项目中的一个答案，我相信它在UI中很好地实现了我的样式目标。表单提交使用纯javascript到一些包含表单。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361933|@using+(Html.BeginForm("Logout",+"Account",+FormMethod.Post,+new+{+id+=+"logoutForm",+@class+=+"navbar-right"+}))
{
+++<a+href="javascript:document.getElementById('logoutForm').submit()">
++++++<span>Sign+out</span>
+++</a>
}|code-block|syntax|javascript|1361934|完整展示的用例是web应用程序导航栏中的注销下拉菜单。|1361935|@using+(Html.BeginForm("Logout",+"Account",+FormMethod.Post,+new+{+id+=+"logoutForm",+@class+=+"navbar-right"+}))
{
++++@Html.AntiForgeryToken()

++++<div+class="dropdown">
++++++++<button+type="button"+class="btn+btn-default+dropdown-toggle"+data-toggle="dropdown">
++++++++++++<span+class="ma-nav-text+ma-account-name">@User.Identity.Name</span>
++++++++++++<i+class="material-icons+md-36+text-inverse">person</i>
++++++++</button>

++++++++<ul+class="dropdown-menu+dropdown-menu-right+ma-dropdown-tray">
++++++++++++<li>
++++++++++++++++<a+href="javascript:document.getElementById('logoutForm').submit()">
++++++++++++++++++++<i+class="material-icons">system_update_alt</i>
++++++++++++++++++++<span>Sign+out</span>
++++++++++++++++</a>
++++++++++++</li>
++++++++</ul>
++++</div>
}|1361936|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<p>Here was an answer baked into the default ASP.NET MVC 5 project I believe that accomplishes my styling goals nicely in the UI. Form submit using pure javascript to some containing form.</p>

<pre><code>@using (Html.BeginForm("Logout", "Account", FormMethod.Post, new { id = "logoutForm", @class = "navbar-right" }))
{
   &lt;a href="javascript:document.getElementById('logoutForm').submit()"&gt;
      &lt;span&gt;Sign out&lt;/span&gt;
   &lt;/a&gt;
}
</code></pre>

<p>The fully shown use case is a logout dropdown in the navigation bar of a web app.</p>

<pre><code>@using (Html.BeginForm("Logout", "Account", FormMethod.Post, new { id = "logoutForm", @class = "navbar-right" }))
{
    @Html.AntiForgeryToken()

    &lt;div class="dropdown"&gt;
        &lt;button type="button" class="btn btn-default dropdown-toggle" data-toggle="dropdown"&gt;
            &lt;span class="ma-nav-text ma-account-name"&gt;@User.Identity.Name&lt;/span&gt;
            &lt;i class="material-icons md-36 text-inverse"&gt;person&lt;/i&gt;
        &lt;/button&gt;

        &lt;ul class="dropdown-menu dropdown-menu-right ma-dropdown-tray"&gt;
            &lt;li&gt;
                &lt;a href="javascript:document.getElementById('logoutForm').submit()"&gt;
                    &lt;i class="material-icons"&gt;system_update_alt&lt;/i&gt;
                    &lt;span&gt;Sign out&lt;/span&gt;
                &lt;/a&gt;
            &lt;/li&gt;
        &lt;/ul&gt;
    &lt;/div&gt;
}
</code></pre>


blocks|key|1146282|text|ActionLink永远不会解雇帖子。它总是触发GET请求。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146283|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

<p>ActionLink will never fire post. It always trigger GET request.</p>


blocks|key|1146257|text|使用以下Call+the+Action+Link：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146258|<%25=+Html.ActionLink("Click+Here"+,+"ActionName","ContorllerName"+)%25>|code-block|syntax|javascript|1146259|要提交表单值，请使用：|1146260|+<%25+using+(Html.BeginForm("CustomerSearchResults",+"Customer"))
+++{+%25>
++++++<input+type="text"+id="Name"+/>
++++++<input+type="submit"+class="dASButton"+value="Submit"+/>
+++<%25+}+%25>|1146261|它会将数据提交给客户控制器和CustomerSearchResults操作。|1146262|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>Use the following the Call the Action Link:</p>

<pre><code>&lt;%= Html.ActionLink("Click Here" , "ActionName","ContorllerName" )%&gt;
</code></pre>

<p>For submitting the form values use:</p>

<pre><code> &lt;% using (Html.BeginForm("CustomerSearchResults", "Customer"))
   { %&gt;
      &lt;input type="text" id="Name" /&gt;
      &lt;input type="submit" class="dASButton" value="Submit" /&gt;
   &lt;% } %&gt;
</code></pre>

<p>It will submit the Data to Customer Controller and CustomerSearchResults Action.</p>


blocks|key|1361975|text|这是从MVC示例项目中提取的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361976|@if+(ViewBag.ShowRemoveButton)
++++++{
+++++++++using+(Html.BeginForm("RemoveLogin",+"Manage"))
+++++++++++{
++++++++++++++@Html.AntiForgeryToken()
++++++++++++++++++<div>
+++++++++++++++++++++@Html.Hidden("company_name",+account)
+++++++++++++++++++++@Html.Hidden("returnUrl",+Model.returnUrl)
+++++++++++++++++++++<input+type="submit"+class="btn+btn-default"+value="Remove"+title="Remove+your+email+address+from+@account"+/>
++++++++++++++++++</div>
++++++++++++}
++++++++}|code-block|syntax|javascript|1361977|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>This is taken from the MVC sample project</p>

<pre><code>@if (ViewBag.ShowRemoveButton)
      {
         using (Html.BeginForm("RemoveLogin", "Manage"))
           {
              @Html.AntiForgeryToken()
                  &lt;div&gt;
                     @Html.Hidden("company_name", account)
                     @Html.Hidden("returnUrl", Model.returnUrl)
                     &lt;input type="submit" class="btn btn-default" value="Remove" title="Remove your email address from @account" /&gt;
                  &lt;/div&gt;
            }
        }
</code></pre>


blocks|key|1146462|text|在Ajax.BeginForm中使用此链接|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146463|@Html.ActionLink(
++++"Save",+
++++"SaveAction",+
++++null,+
++++null,+
++++onclick+=+"$(this).parents('form').attr('action',+$(this).attr('href'));$(this).parents('form').submit();return+false;"+})|code-block|syntax|javascript|1146464|;)|1146465|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>Use this link inside Ajax.BeginForm</p>

<pre><code>@Html.ActionLink(
    "Save", 
    "SaveAction", 
    null, 
    null, 
    onclick = "$(this).parents('form').attr('action', $(this).attr('href'));$(this).parents('form').submit();return false;" })
</code></pre>

<p>;)</p>


blocks|key|1361461|text|我对这个问题的解决方案非常简单。我有一个页面，一个按整个电子邮件搜索客户，另一个按部分搜索，部分拉取并显示一个列表。该列表有一个操作链接，指向名为GetByID的操作结果，并传入id|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361462|GetByID提取所选客户的数据，然后返回|1361463|return+View("Index",+model);+|code-block|syntax|javascript|1361464|哪一个是post方法？|1361465|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<p>My Solution to this issue is a fairly simple one. I have a page that does a customer search one by the whole email and the other by a partial, the partial pulls and displays a list the list has an action link that points to a actionresult called GetByID and passes in the id</p>

<p>the GetByID pulls the data for the selected customer then returns </p>

<pre><code>return View("Index", model); 
</code></pre>

<p>which is the post method</p>


blocks|key|1146552|text|这对我来说是一个很难解决的问题。如何在razor和html中构建动态链接，以调用操作方法并将一个或多个值传递给特定的操作方法？我考虑了几个选项，包括自定义的html+helper。我只是想出了一个简单而优雅的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146553|视图|1146554|@model+IEnumerable<MyMvcApp.Models.Product>

@using+(Html.BeginForm())+{

+++++<table>
+++++++++<thead>
+++++++++++++<tr>
+++++++++++++++++<td>Name</td>
+++++++++++++++++<td>Price</td>
+++++++++++++++++<td>Quantity</td>
++++++++++++</tr>
++++++++</thead>
++++++++@foreach+(Product+p+in+Model.Products)
++++++++{
++++++++++++<tr>
++++++++++++++++<td><a+href="@Url.Action("Edit",+"Product",+p)">@p.Name</a></td>
++++++++++++++++<td>@p.Price.ToString()</td>
++++++++++++++++<td>@p.Quantity.ToString()</td>
++++++++++++</tr>
+++++++++}
++++</table>
}|code-block|syntax|javascript|1146555|动作方法|1146556|public+ViewResult+Edit(Product+prod)
{
++++ContextDB+contextDB+=+new+ContextDB();

++++Product+product+=+contextDB.Products.Single(p+=>+p.ProductID+==+prod.ProductId);

++++product+=+prod;

++++contextDB.SaveChanges();

++++return+View("Edit");
}|1146557|这里的要点是，Url.Action并不关心操作方法是GET还是POST。它可以访问这两种方法中的任何一种。您可以使用以下命令将数据传递给操作方法|1146558|@Url.Action(string+actionName,+string+controllerName,+object+routeValues)|1146559|routeValues对象。我已经试过了，它很管用。不，从技术上讲，您不是在做post或提交表单，但是如果routeValues对象包含您的数据，那么它是post还是get都无关紧要。您可以使用特定的操作方法签名来选择正确的方法。|1146560|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

<p>This has been a difficult problem for me to solve.  How can I build a dynamic link in razor and html that can call an action method and pass a value or values to a specific action method?  I considered several options including a custom html helper.  I just came up with a simple and elegant solution. </p>

<p>The view</p>

<pre><code>@model IEnumerable&lt;MyMvcApp.Models.Product&gt;

@using (Html.BeginForm()) {

     &lt;table&gt;
         &lt;thead&gt;
             &lt;tr&gt;
                 &lt;td&gt;Name&lt;/td&gt;
                 &lt;td&gt;Price&lt;/td&gt;
                 &lt;td&gt;Quantity&lt;/td&gt;
            &lt;/tr&gt;
        &lt;/thead&gt;
        @foreach (Product p in Model.Products)
        {
            &lt;tr&gt;
                &lt;td&gt;&lt;a href="@Url.Action("Edit", "Product", p)"&gt;@p.Name&lt;/a&gt;&lt;/td&gt;
                &lt;td&gt;@p.Price.ToString()&lt;/td&gt;
                &lt;td&gt;@p.Quantity.ToString()&lt;/td&gt;
            &lt;/tr&gt;
         }
    &lt;/table&gt;
}
</code></pre>

<p>The action method</p>

<pre><code>public ViewResult Edit(Product prod)
{
    ContextDB contextDB = new ContextDB();

    Product product = contextDB.Products.Single(p =&gt; p.ProductID == prod.ProductId);

    product = prod;

    contextDB.SaveChanges();

    return View("Edit");
}
</code></pre>

<p>The point here is that Url.Action does not care whether the action method is a GET or a POST.   It will access either type of method.   You can pass your data to the action method using </p>

<pre><code>@Url.Action(string actionName, string controllerName, object routeValues)
</code></pre>

<p>the routeValues object.  I have tried this and it works.  No, you are not technically doing a post or submitting the form but if the routeValues object contains your data, it doesnt matter if its a post or a get.   You can use a particular action method signature to select the right method.</p>


blocks|key|1146730|text|我已经使用以下代码完成了相同的问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146731|@using+(Html.BeginForm("Delete",+"Admin"))
{
+++++++@Html.Hidden("ProductID",+item.ProductID)
+++++++<input+type="submit"+value="Delete"+/>
}|code-block|syntax|javascript|1146732|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>I have done the same issue using following code:</p>

<pre><code>@using (Html.BeginForm("Delete", "Admin"))
{
       @Html.Hidden("ProductID", item.ProductID)
       &lt;input type="submit" value="Delete" /&gt;
}
</code></pre>


blocks|key|1361119|text|如果您有自定义数据，则jQuery.post()将起作用。如果你想发布现有的表单，使用ajaxSubmit()会更容易。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1361120|而且您不必在ActionLink本身中设置此代码，因为您可以在document.ready()事件中附加链接处理程序(无论如何，这是一种首选方法)，例如使用$(function(){+...+})+jQuery技巧。|1361121|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.jquery.com/Ajax/jQuery.post|1|http://jquery.malsup.com/form/#api^0|B|D|17|C|B|D|0|17|C|1|0|6|A|V|G|26|K|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@$9|W|A|X|1|Y]|$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]|P|$5|K|L|M|E|$N|Q]]]]

<p><a href="http://docs.jquery.com/Ajax/jQuery.post" rel="nofollow noreferrer"><code>jQuery.post()</code></a> will work if you have custom data. If you want to post existing form, it's easier to use <a href="http://jquery.malsup.com/form/#api" rel="nofollow noreferrer"><code>ajaxSubmit()</code></a>.</p>

<p>And you don't have to setup this code in the <code>ActionLink</code> itself, since you can attach link handler in the <code>document.ready()</code> event (which is a preferred method anyway), for example using <code>$(function(){ ... })</code> jQuery trick.</p>


blocks|key|1146389|text|我建议保持对REST原则的纯正，并使用HTTP+delete删除您的删除。不幸的是，HTML规范只有HTTP+Get和Post。标记只能是HTTP+Get。表单标记可以执行HTTP+Get或Post。幸运的是，如果你使用ajax，你可以做一个HTTP删除，这是我推荐的。有关详细信息，请参阅以下帖子：Http+Deletes|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1146390|entityMap|0|LINK|mutability|MUTABLE|url|http://stephenwalther.com/blog/archive/2009/01/21/asp.net-mvc-tip-46-ndash-donrsquot-use-delete-links-because.aspx^0|46|C|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

<p>I would recommend staying pure to REST principles and using an HTTP delete for your deletes. Unfortunately HTML Specs only has HTTP Get &amp; Post. A tag only can a HTTP Get. A form tag can either do a HTTP Get or Post. Fortunately if you use ajax you can do a HTTP Delete and this is what i recommend. See the following post for details: <a href="http://stephenwalther.com/blog/archive/2009/01/21/asp.net-mvc-tip-46-ndash-donrsquot-use-delete-links-because.aspx" rel="nofollow">Http Deletes</a></p>


blocks|key|1146790|text|遇到这个需要从搜索(索引)页面发布到结果页面。我不需要像@Vitaliy所说的那样多，但它为我指明了正确的方向。我所要做的就是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1146791|@using+(Html.BeginForm("Result",+"Search",+FormMethod.Post))+{
++<div+class="row">
++++<div+class="col-md-4">
++++++<div+class="field">Search+Term:</div>
++++++<input+id="k"+name="k"+type="text"+placeholder="Search"+/>
++++</div>
++</div>
++<br+/>
++<div+class="row">
++++<div+class="col-md-12">
++++++<button+type="submit"+class="btn+btn-default">Search</button>
++++</div>
++</div>
}|code-block|syntax|javascript|1146792|我的控制器有以下签名方法：|1146793|[HttpPost]
public+async+Task<ActionResult>+Result(string+k)|1146794|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<p>Came across this needing to POST from a Search (Index) page to the Result page. I did not need as much as @Vitaliy stated but it pointed me in the right direction. All I had to do was this:</p>

<pre><code>@using (Html.BeginForm("Result", "Search", FormMethod.Post)) {
  &lt;div class="row"&gt;
    &lt;div class="col-md-4"&gt;
      &lt;div class="field"&gt;Search Term:&lt;/div&gt;
      &lt;input id="k" name="k" type="text" placeholder="Search" /&gt;
    &lt;/div&gt;
  &lt;/div&gt;
  &lt;br /&gt;
  &lt;div class="row"&gt;
    &lt;div class="col-md-12"&gt;
      &lt;button type="submit" class="btn btn-default"&gt;Search&lt;/button&gt;
    &lt;/div&gt;
  &lt;/div&gt;
}
</code></pre>

<p>My Controller had the following signature method:</p>

<pre><code>[HttpPost]
public async Task&lt;ActionResult&gt; Result(string k)
</code></pre>


<p>Can anyone tell me how can I submit values to Controller using ActionLink and POST method?<br />
I don't want to use buttons.<br />
I guess it has something with jquery.<br /></p>


ASP.NET MVC ActionLink and post method

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谁能告诉我如何使用ActionLink和POST方法向控制器提交值？我不想用按钮。我猜它与jquery有关。

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