blocks|key|1848097|text|我建议使用perl。(\d%2B.\d%2B)应该可以做到这一点。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1848098|编辑:只是为了让它更像一个完整的程序，你可以这样做(未测试)：|1848099|#!/usr/bin/perl+-w
use+strict;

while+(<>)+{
++++if+(/(\d%2B\.\d%2B\.\d%2B\.\d%2B)/)+{
++++++++print+"$1\n";
++++}
}|code-block|syntax|javascript|1848100|这将处理每行一个IP。如果每行有多个If，则需要使用/g选项。man+perlretut为您提供了有关正则表达式的更详细的教程。|1848101|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I'd suggest perl. (\d+.\d+.\d+.\d+) should probably do the trick. 

EDIT: Just to make it more like a complete program, you could do something like the following (not tested): 

<pre><code>#!/usr/bin/perl -w
use strict;

while (&lt;&gt;) {
 if (/(\d+\.\d+\.\d+\.\d+)/) {
 print "$1\n";
 }
}
</code></pre>

This handles one IP per line. If you have more than one IPs per line, you need to use the /g option. man perlretut gives you a more detailed tutorial on regular expressions.

blocks|key|1848108|text|您可以使用grep将它们提取出来。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1848109|grep+-o+'[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}'+file.txt|code-block|syntax|javascript|1848110|entityMap|0|LINK|mutability|MUTABLE|url|http://unixhelp.ed.ac.uk/CGI/man-cgi?grep^0|5|4|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You could use <a href="http://unixhelp.ed.ac.uk/CGI/man-cgi?grep" rel="noreferrer">grep</a> to pull them out.

<pre><code>grep -o '[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}' file.txt
</code></pre>

blocks|key|2062173|text|您可以使用sed。但是，如果您了解perl，从长远来看，这可能会更容易，也更有用：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2062174|perl+-n+'/(\d%2B\.\d%2B\.\d%2B\.\d%2B)/+&&+print+"$1\n"'+<+file|code-block|syntax|javascript|2062175|entityMap|0|LINK|mutability|MUTABLE|url|http://www.grymoire.com/Unix/Sed.html^0|5|3|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can use <a href="http://www.grymoire.com/Unix/Sed.html" rel="nofollow noreferrer">sed</a>. But if you know perl, that might be easier, and more useful to know in the long run:

<pre><code>perl -n '/(\d+\.\d+\.\d+\.\d+)/ &amp;&amp; print "$1\n"' &lt; file
</code></pre>

blocks|key|1848154|text|你也可以使用awk。就像..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1848155|awk+'{i=1;+if+(NF+>+0)+do+{if+($i+~+/regexp/)+print+$i;+i%2B%2B;}+while+(i+<=+NF);}'+file|code-block|syntax|javascript|1848156|可能需要清洗。只是对的快速而肮脏的响应，基本上展示了如何使用awk来做这件事。|1848157|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could use awk, as well. Something like ...

<pre><code>awk '{i=1; if (NF &gt; 0) do {if ($i ~ /regexp/) print $i; i++;} while (i &lt;= NF);}' file
</code></pre>

May require cleaning. just a quick and dirty response to shows basically how to do it with awk.

blocks|key|2062232|text|我通常从grep开始，以获得正确的regexp。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2062233|#+[multiple+failed+attempts+here]
grep++++'[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*'+++++++++++++++++file++#+good?
grep+-E+'[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}'+file++#+good+enough|code-block|syntax|javascript|2062234|然后，我会尝试将其转换为sed，以过滤掉该行的其余部分。(读完这篇文章后，你和我不会再这样做了:我们将使用grep+-o。)|offset|length|style|CODE|2062235|sed+-ne+'s/.*$[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$.*/\1/p++#+FAIL|2062236|这就是我通常对sed不像其他人一样使用相同的正则表达式而感到恼火的时候。所以我搬到了perl。|2062237|$+perl+-nle+'/[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}/+and+print+$&'|2062238|无论如何，Perl都很高兴知道这一点。如果您安装了少量的CPAN，您甚至可以以很少的成本使其更加可靠：|2062239|$+perl+-MRegexp::Common=net+-nE+'/$RE{net}{IPV4}/+and+say+$&'+file(s)|2062240|entityMap^0|0|0|C|3|1H|7|0|0|7|3|16|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@$I|11|J|12|K|L]|$I|13|J|14|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|16|8|@$I|17|J|18|K|L]|$I|19|J|1A|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1C|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|W|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|X|$]]

I usually start with grep, to get the regexp right.

<pre><code># [multiple failed attempts here]
grep '[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*' file # good?
grep -E '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}' file # good enough
</code></pre>

Then I'd try and convert it to <code>sed</code> to filter out the rest of the line. (After reading this thread, you and I aren't going to do that anymore: we're going to use <code>grep -o</code> instead)

<pre><code>sed -ne 's/.*$[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$.*/\1/p # FAIL
</code></pre>

That's when I usually get annoyed with <code>sed</code> for not using the same regexes as anyone else. So I move to <code>perl</code>.

<pre><code>$ perl -nle '/[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}/ and print $&amp;'
</code></pre>

Perl's good to know in any case. If you've got a teeny bit of CPAN installed, you can even make it more reliable at little cost:

<pre><code>$ perl -MRegexp::Common=net -nE '/$RE{net}{IPV4}/ and say $&amp;' file(s)
</code></pre>

blocks|key|2062268|text|这里的大多数示例都将匹配999.999.999.999，从技术上讲，这不是一个有效的IP地址。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2062269|以下内容将仅匹配有效的IP地址(包括网络和广播地址)。|2062270|grep+-E+-o+'(25[0-5]%7C2[0-4][0-9]%7C[01]?[0-9][0-9]?)\.(25[0-5]%7C2[0-4][0-9]%7C[01]?[0-9][0-9]?)\.(25[0-5]%7C2[0-4][0-9]%7C[01]?[0-9][0-9]?)\.(25[0-5]%7C2[0-4][0-9]%7C[01]?[0-9][0-9]?)'+file.txt|code-block|syntax|javascript|2062271|如果要查看匹配的整个行，请省略-o。|2062272|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Most of the examples here will match on 999.999.999.999 which is not technically a valid IP address.

The following will match on only valid IP addresses (including network and broadcast addresses).

<pre><code>grep -E -o '(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)' file.txt
</code></pre>

Omit the -o if you want to see the entire line that matched.

blocks|key|1848233|text|为了更好地查看我的日志文件，我编写了一个小script，它没有什么特别之处，但可能会对很多正在学习perl的人有所帮助。它在提取IP地址后对其进行DNS查找。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1848234|entityMap|0|LINK|mutability|MUTABLE|url|http://digitalcrunch.com/perl/extract-ipv4-address-from-text-using-perl/^0|L|6|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

I wrote a little <a href="http://digitalcrunch.com/perl/extract-ipv4-address-from-text-using-perl/" rel="nofollow">script</a> to see my log files better, it's nothing special, but might help a lot of the people who are learning perl. It does DNS lookups on the IP addresses after it extracts them.

blocks|key|1848244|text|对于centos6.3|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1848245|ifconfig+eth0+%7C+grep+'inet+addr'+%7C+awk+'{print+$2}'+%7C+awk+'BEGIN+{FS=":"}+{print+$2}'|offset|length|style|CODE|1848246|entityMap^0|0|0|2D|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

for centos6.3

<code>ifconfig eth0 | grep 'inet addr' | awk '{print $2}' | awk 'BEGIN {FS=":"} {print $2}'</code>

blocks|key|1848250|text|+grep+-E+-o+"([0-9]{1,3}[\.]){3}[0-9]{1,3}"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1848251|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|1848262|text|如果你没有得到一个特定的文件，你需要提取IP地址，那么我们需要递归地进行提取。grep命令->搜索文本或文件以匹配给定的字符串，并显示匹配的字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1848263|grep+-roE+'[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}'+%7C+grep+-oE+'[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}'|code-block|syntax|javascript|1848264|-r我们可以搜索整个目录树，即当前目录和各级子目录。它表示递归搜索。|offset|length|style|CODE|1848265|-o仅打印匹配的字符串|1848266|-E使用扩展正则表达式|1848267|如果我们没有在管道后面使用第二个grep命令，我们将获得IP地址以及它所在的路径|1848268|entityMap^0|0|0|0|2|0|0|2|0|0|2|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@$I|10|J|11|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@$I|13|J|14|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|T|$]]

If you are not given a specific file and you need to extract IP address then we need to do it recursively.
grep command -> Searches a text or file for matching a given string and displays the matched string .

<pre><code>grep -roE '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}' | grep -oE '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}'
</code></pre>

<code>-r</code> We can search the entire directory tree i.e. the current directory and all levels of sub-directories. It denotes recursive searching.

<code>-o</code> Print only the matching string

<code>-E</code> Use extended regular expression

If we would not have used the second grep command after the pipe we would have got the IP address along with the path where it is present

blocks|key|2062348|text|cat+ip_address.txt+%7C+grep+'%5E[0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[,].*$\%7C%5E.*[,][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[,].*$\%7C%5E.*[,][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}$'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2062349|让我们假设文件是逗号分隔的，ip地址的位置在开头、结尾和中间的某个位置|unstyled|2062350|首先，regexp在行首查找与ip地址完全匹配的内容。或在middle.we中查找ip地址后的第二个正则表达式以这样的方式匹配它，即后面的数字应该正好是1到3位.falsy+ip，例如12345.12.34.1可以排除在此之外。|2062351|第三个regexp在行尾查找ip地址|2062352|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>cat ip_address.txt | grep '^[0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[,].*$\|^.*[,][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[,].*$\|^.*[,][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}[.][0-9]\{1,3\}$'
</code></pre>

Lets assume the file is comma delimited and the position of ip address in the beginning ,end and somewhere in the middle

First regexp looks for the exact match of ip address in the beginning of the line.
The second regexp after the or looks for ip address in the middle.we are matching it in such a way that the number that follows ,should be exactly 1 to 3 digits .falsy ips like 12345.12.34.1 can be excluded in this.

The third regexp looks for the ip address at the end of the line

blocks|key|1848311|text|前面的所有答案都有一个或多个问题。接受的答案允许像999.999.999.999这样的ip号码。当前支持率第二高的答案需要以0为前缀，例如127.000.000.001或008.008.008.008，而不是127.0.0.1或8.8.8.8。Apama几乎是正确的，但该表达式要求ipnumber是一行中唯一的内容，不允许前导或尾随空格，也不能从行的中间选择ip。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1848312|我认为在http://www.regextester.com/22上可以找到正确的正则表达式。|offset|length|1848313|因此，如果您想从一个文件中提取所有ip地址，请使用：|1848314|grep+-Eo+"(([0-9]%7C[1-9][0-9]%7C1[0-9]{2}%7C2[0-4][0-9]%7C25[0-5])\.){3}([0-9]%7C[1-9][0-9]%7C1[0-9]{2}%7C2[0-4][0-9]%7C25[0-5])"+file.txt|code-block|syntax|javascript|1848315|如果您不想使用重复项，请使用：|1848316|grep+-Eo+"(([0-9]%7C[1-9][0-9]%7C1[0-9]{2}%7C2[0-4][0-9]%7C25[0-5])\.){3}([0-9]%7C[1-9][0-9]%7C1[0-9]{2}%7C2[0-4][0-9]%7C25[0-5])"+file.txt+%7C+sort+%7C+uniq|1848317|如果此正则表达式中仍然存在问题，请发表意见。这个问题很容易找到很多错误的正则表达式，我希望这个没有真正的问题。|1848318|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regextester.com/22^0|0|4|T|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@]|9|@$D|12|E|13|1|14]]|A|$]]|$1|F|3|G|5|6|7|15|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|16|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|17|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|18|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|19|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

All of the previous answers have one or more problems. The accepted answer allows ip numbers like 999.999.999.999. The currently second most upvoted answer requires prefixing with 0 such as 127.000.000.001 or 008.008.008.008 instead of 127.0.0.1 or 8.8.8.8. Apama has it almost right, but that expression requires that the ipnumber is the only thing on the line, no leading or trailing space allowed, nor can it select ip's from the middle of a line.

I think the correct regex can be found on <a href="http://www.regextester.com/22" rel="nofollow noreferrer">http://www.regextester.com/22</a>

So if you want to extract all ip-adresses from a file use:

<pre><code>grep -Eo "(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])" file.txt
</code></pre>

If you don't want duplicates use:

<pre><code>grep -Eo "(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])" file.txt | sort | uniq
</code></pre>

Please comment if there still are problems in this regex. It easy to find many wrong regex for this problem, I hope this one has no real issues.

blocks|key|2062384|text|这里的每个人都在使用非常冗长的正则表达式，但实际上理解POSIX的正则表达式将允许您使用像这样的小grep命令来打印IP地址。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2062385|grep+-Eo+"(([0-9]{1,3})\.){3}([0-9]{1,3})"|code-block|syntax|javascript|2062386|(旁注)这不会忽略无效的is，但它非常简单。|2062387|entityMap^0|1D|4|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

Everyone here is using really long-handed regular expressions but actually understanding the regex of POSIX will allow you to use a small <code>grep</code> command like this for printing IP addresses.

<pre><code>grep -Eo "(([0-9]{1,3})\.){3}([0-9]{1,3})"
</code></pre>

(Side note)
This doesn't ignore invalid IPs but it is very simple.

blocks|key|2062404|text|我只想从目录中的任何文件中获取以"10“开头的IP地址：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2062405|grep+-o+-nr+"[10]\{2\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}"+/var/www|code-block|syntax|javascript|2062406|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I wanted to get only IP addresses that began with "10", from any file in a directory:

<pre><code>grep -o -nr "[10]\{2\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}" /var/www
</code></pre>

How to extract a text part by regexp in linux shell? Lets say, I have a file where in every line is an IP address, but on a different position. What is the simplest way to extract those IP addresses using common unix command-line tools?

How do you extract IP addresses from files using a regex in a linux shell?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何在linux shell中使用regexp提取文本部分？假设我有一个文件，其中每一行都有一个IP地址，但位置不同。使用常用unix命令行工具提取这些IP地址的最简单方法是什么？

问如何在linux shell中使用regex从文件中提取IP地址？
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问如何在linux shell中使用regex从文件中提取IP地址？EN