问如何轻松地将INI文件中的数组解析为C中的数组？

EN

arr = val1, val2, ..., valn

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <confini.h>

struct my_conf_T {
    size_t arrlen;
    char ** arr;
};

static int my_listnr (IniDispatch * this, void * v_conf) {
    #define conf ((struct my_conf_T *) v_conf)
    if (ini_string_match_si("arr", this->data, this->format)) {
        conf->arrlen = ini_array_get_length(this->value, INI_COMMA, this->format);
        if (!conf->arrlen || !this->v_len) {
            /*  Array is empty  */
            return 0;
        }
        conf->arr = (char **) malloc(conf->arrlen * sizeof(char *) + this->v_len + 1);
        if (!conf->arr) {
            fprintf(stderr, "malloc() failed\n");
            exit(1);
        }
        char * remnant = (char *) ((char **) conf->arr + conf->arrlen);
        memcpy(remnant, this->value, this->v_len + 1);
        for (size_t idx = 0; idx < conf->arrlen; idx++) {
            conf->arr[idx] = ini_array_release(&remnant, INI_COMMA, this->format);
            ini_string_parse(conf->arr[idx], this->format);
        }
    }
    return 0;
    #undef conf
}

int main () {
    struct my_conf_T my_conf = (struct my_conf_T) { 0 };
    if (load_ini_path("test.conf", INI_DEFAULT_FORMAT, NULL, my_listnr, &my_conf)) {
        fprintf(stderr, "Sorry, something went wrong :-(\n");
        return 1;
    }
    if (my_conf.arr) {
        /*  Do something with `my_conf.arr`...  */
        for (size_t idx = 0; idx < my_conf.arrlen; idx++) {
            printf("arr[%zu] = %s\n", idx, my_conf.arr[idx]);
        }
        free(my_conf.arr);
    }
    return 0;
}

arr[0] = val1
arr[1] = val2
arr[2] = ...
arr[3] = valn