entityMap|blocks|key|2aks2|text|您应该从zip文件中获取所有条目：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|fnjri|Enumeration+entries+=+zipFile.getEntries();|code-block|syntax|javascript|31tuv|然后对此枚举进行迭代，以获取|clvat|从其中检查是否为目录，并分别创建目录或仅解压缩一个文件。^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|L|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|M|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|N|9|@]|A|@]|B|$]]|$2|J|4|K|6|7|8|O|9|@]|A|@]|B|$]]]]

You should get all entries from your zip file:

<pre><code>Enumeration entries = zipFile.getEntries();
</code></pre>

Then iterating over this enumeration get the <code>ZipEntry</code> from it, check whether it is a directory or not, and create directory or just extract a file respectively.

entityMap|blocks|key|cbo5e|text|这是我使用的代码。更改缓冲区|type|unstyled|depth|inlineStyleRanges|entityRanges|data|dqohs|_|cm75k|尺寸满足您的需求。|3kndp|import+java.io.BufferedOutputStream;
import+java.io.File;
import+java.io.FileOutputStream;
import+java.io.IOException;
import+java.util.zip.ZipEntry;
import+java.util.zip.ZipInputStream;

public+final+class+ZipUtils+{

++++private+static+final+int+BUFFER_SIZE+=+4096;

++++public+static+void+extract(ZipInputStream+zip,+File+target)+throws+IOException+{
++++++++try+{
++++++++++++ZipEntry+entry;

++++++++++++while+((entry+=+zip.getNextEntry())+!=+null)+{
++++++++++++++++File+file+=+new+File(target,+entry.getName());

++++++++++++++++if+(!file.toPath().normalize().startsWith(target.toPath()))+{
++++++++++++++++++++throw+new+IOException("Bad+zip+entry");
++++++++++++++++}

++++++++++++++++if+(entry.isDirectory())+{
++++++++++++++++++++file.mkdirs();
++++++++++++++++++++continue;
++++++++++++++++}

++++++++++++++++byte[]+buffer+=+new+byte[BUFFER_SIZE];
++++++++++++++++file.getParentFile().mkdirs();
++++++++++++++++BufferedOutputStream+out+=+new+BufferedOutputStream(new+FileOutputStream(file));
++++++++++++++++int+count;

++++++++++++++++while+((count+=+zip.read(buffer))+!=+-1)+{
++++++++++++++++++++out.write(buffer,+0,+count);
++++++++++++++++}

++++++++++++++++out.close();
++++++++++++}
++++++++}+finally+{
++++++++++++zip.close();
++++++++}
++++}

}|code-block|syntax|javascript^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|L|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|M|9|@]|A|@]|B|$]]|$2|E|4|F|6|7|8|N|9|@]|A|@]|B|$]]|$2|G|4|H|6|I|8|O|9|@]|A|@]|B|$J|K]]]]

Here is the code I'm using. Change BUFFER_SIZE for your needs.

<pre><code>import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public final class ZipUtils {

 private static final int BUFFER_SIZE = 4096;

 public static void extract(ZipInputStream zip, File target) throws IOException {
 try {
 ZipEntry entry;

 while ((entry = zip.getNextEntry()) != null) {
 File file = new File(target, entry.getName());

 if (!file.toPath().normalize().startsWith(target.toPath())) {
 throw new IOException("Bad zip entry");
 }

 if (entry.isDirectory()) {
 file.mkdirs();
 continue;
 }

 byte[] buffer = new byte[BUFFER_SIZE];
 file.getParentFile().mkdirs();
 BufferedOutputStream out = new BufferedOutputStream(new FileOutputStream(file));
 int count;

 while ((count = zip.read(buffer)) != -1) {
 out.write(buffer, 0, count);
 }

 out.close();
 }
 } finally {
 zip.close();
 }
 }

}
</code></pre>

entityMap|blocks|key|2o9vi|text|使用Ant压缩库也可以做到这一点。它将保留文件夹结构。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1o2qh|Maven依赖：-|9u394|org.apache.ant
++++ant-compress
++++1.2|code-block|syntax|javascript|554mk|示例代码：-|hfv6|Unzip+unzipper+=+new+Unzip();
unzipper.setSrc(theZIPFile);
unzipper.setDest(theTargetFolder);
unzipper.execute();^0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|N|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|O|9|@]|A|@]|B|$]]|$2|E|4|F|6|G|8|P|9|@]|A|@]|B|$H|I]]|$2|J|4|K|6|7|8|Q|9|@]|A|@]|B|$]]|$2|L|4|M|6|G|8|R|9|@]|A|@]|B|$H|I]]]]

Same can be achieved using Ant Compress library. It will preserve the folder structure.

Maven dependency:-

<pre><code>&lt;dependency&gt;
 &lt;groupId&gt;org.apache.ant&lt;/groupId&gt;
 &lt;artifactId&gt;ant-compress&lt;/artifactId&gt;
 &lt;version&gt;1.2&lt;/version&gt;
&lt;/dependency&gt;
</code></pre>

Sample code:-

<pre><code>Unzip unzipper = new Unzip();
unzipper.setSrc(theZIPFile);
unzipper.setDest(theTargetFolder);
unzipper.execute();
</code></pre>

entityMap|blocks|key|ev62i|text|我不确定你说的具体是什么意思？你的意思是没有API帮助的情况下自己做吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|48lub|如果你不介意使用一些开源库，有一个很酷的API，叫做|5ru9o|zip4J|59qo3|它很容易使用，我认为有很好的反馈。请参阅此示例：|671me|String+source+=+"folder/source.zip";
String+destination+=+"folder/source/";+++

try+{
++++ZipFile+zipFile+=+new+ZipFile(source);
++++zipFile.extractAll(destination);
}+catch+(ZipException+e)+{
++++e.printStackTrace();
}|code-block|syntax|javascript|2u7r1|如果你想解压的文件有密码，你可以尝试这样做：|3se1b|String+source+=+"folder/source.zip";
String+destination+=+"folder/source/";
String+password+=+"password";

try+{
++++ZipFile+zipFile+=+new+ZipFile(source);
++++if+(zipFile.isEncrypted())+{
++++++++zipFile.setPassword(password);
++++}
++++zipFile.extractAll(destination);
}+catch+(ZipException+e)+{
++++e.printStackTrace();
}|995c8|我希望这是有用的。^0|0|0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|T|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|U|9|@]|A|@]|B|$]]|$2|E|4|F|6|7|8|V|9|@]|A|@]|B|$]]|$2|G|4|H|6|7|8|W|9|@]|A|@]|B|$]]|$2|I|4|J|6|K|8|X|9|@]|A|@]|B|$L|M]]|$2|N|4|O|6|7|8|Y|9|@]|A|@]|B|$]]|$2|P|4|Q|6|K|8|Z|9|@]|A|@]|B|$L|M]]|$2|R|4|S|6|7|8|10|9|@]|A|@]|B|$]]]]

I am not sure what do you mean by particaly? 
Do you mean do it yourself without of API help?

In the case you don't mind using some opensource library,
there is a cool API for that out there called <a href="http://www.lingala.net/zip4j/" rel="noreferrer">zip4J</a>

It is easy to use and I think there is good feedback about it. 
See this example:

<pre><code>String source = "folder/source.zip";
String destination = "folder/source/"; 

try {
 ZipFile zipFile = new ZipFile(source);
 zipFile.extractAll(destination);
} catch (ZipException e) {
 e.printStackTrace();
}
</code></pre>

If the files you want to unzip have passwords, you can try this:

<pre><code>String source = "folder/source.zip";
String destination = "folder/source/";
String password = "password";

try {
 ZipFile zipFile = new ZipFile(source);
 if (zipFile.isEncrypted()) {
 zipFile.setPassword(password);
 }
 zipFile.extractAll(destination);
} catch (ZipException e) {
 e.printStackTrace();
}
</code></pre>

I hope this is useful.

entityMap|blocks|key|20n6m|text|这里有一个简单的解决方案，它遵循更现代的约定。如果您要解压缩较大的文件，则可能需要将缓冲区大小更改为较小。这样你就不会把所有的文件信息都保存在内存中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|eagvf|public+static+void+unzip(File+source,+String+out)+throws+IOException+{
++++try+(ZipInputStream+zis+=+new+ZipInputStream(new+FileInputStream(source)))+{

++++++++ZipEntry+entry+=+zis.getNextEntry();

++++++++while+(entry+!=+null)+{

++++++++++++File+file+=+new+File(out,+entry.getName());

++++++++++++if+(entry.isDirectory())+{
++++++++++++++++file.mkdirs();
++++++++++++}+else+{
++++++++++++++++File+parent+=+file.getParentFile();

++++++++++++++++if+(!parent.exists())+{
++++++++++++++++++++parent.mkdirs();
++++++++++++++++}

++++++++++++++++try+(BufferedOutputStream+bos+=+new+BufferedOutputStream(new+FileOutputStream(file)))+{

++++++++++++++++++++int+bufferSize+=+Math.toIntExact(entry.getSize());
++++++++++++++++++++byte[]+buffer+=+new+byte[bufferSize+>+0+?+bufferSize+:+1];
++++++++++++++++++++int+location;

++++++++++++++++++++while+((location+=+zis.read(buffer))+!=+-1)+{
++++++++++++++++++++++++bos.write(buffer,+0,+location);
++++++++++++++++++++}
++++++++++++++++}
++++++++++++}
++++++++++++entry+=+zis.getNextEntry();
++++++++}
++++}
}|code-block|syntax|javascript^0|0^^$0|$]|1|@$2|3|4|5|6|7|8|H|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|I|9|@]|A|@]|B|$F|G]]]]

Here's an easy solution which follows more modern conventions. You may want to change the buffer size to be smaller if you're unzipping larger files. This is so you don't keep all of the files info in-memory.

<pre><code> public static void unzip(File source, String out) throws IOException {
 try (ZipInputStream zis = new ZipInputStream(new FileInputStream(source))) {

 ZipEntry entry = zis.getNextEntry();

 while (entry != null) {

 File file = new File(out, entry.getName());

 if (entry.isDirectory()) {
 file.mkdirs();
 } else {
 File parent = file.getParentFile();

 if (!parent.exists()) {
 parent.mkdirs();
 }

 try (BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(file))) {

 int bufferSize = Math.toIntExact(entry.getSize());
 byte[] buffer = new byte[bufferSize &gt; 0 ? bufferSize : 1];
 int location;

 while ((location = zis.read(buffer)) != -1) {
 bos.write(buffer, 0, location);
 }
 }
 }
 entry = zis.getNextEntry();
 }
 }
}
</code></pre>

entityMap|blocks|key|b057v|text|下面是更“现代”的完整代码，基于|type|unstyled|depth|inlineStyleRanges|entityRanges|data|222o9|这个|ep5sp|post但已重构(并使用|d0kvp|)：|cvdv9|import+lombok.var;
import+lombok.val;

import+java.io.File;
import+java.io.FileInputStream;
import+java.io.FileOutputStream;
import+java.io.IOException;
import+java.util.zip.ZipInputStream;

import+static+java.nio.file.Files.createDirectories;

public+class+UnZip
{
++++public+static+void+unZip(String+sourceZipFile,+String+outputDirectory)+throws+IOException
++++{
++++++++val+folder+=+new+File(outputDirectory);
++++++++createDirectories(folder.toPath());

++++++++try+(val+zipInputStream+=+new+ZipInputStream(new+FileInputStream(sourceZipFile,+Charset.forName("Cp437"))))
++++++++{
++++++++++++var+nextEntry+=+zipInputStream.getNextEntry();

++++++++++++while+(nextEntry+!=+null)
++++++++++++{
++++++++++++++++val+fileName+=+nextEntry.getName();
++++++++++++++++val+newFile+=+new+File(outputDirectory+%2B+File.separator+%2B+fileName);

++++++++++++++++newFile.getParentFile().mkdirs();

++++++++++++++++if(fileName.endsWith("/")){
++++++++++++++++++++newFile.mkdirs();
++++++++++++++++}+else+{
++++++++++++++++++++writeFile(zipInputStream,+newFile);
++++++++++++++++}

++++++++++++++++writeFile(zipInputStream,+newFile);

++++++++++++++++nextEntry+=+zipInputStream.getNextEntry();
++++++++++++}

++++++++++++zipInputStream.closeEntry();
++++++++}
++++}

++++private+static+void+writeFile(ZipInputStream+inputStream,+File+file)+throws+IOException
++++{
++++++++val+buffer+=+new+byte[1024];
++++++++file.createNewFile();
++++++++try+(val+fileOutputStream+=+new+FileOutputStream(file))
++++++++{
++++++++++++int+length;
++++++++++++while+((length+=+inputStream.read(buffer))+>+0)
++++++++++++{
++++++++++++++++fileOutputStream.write(buffer,+0,+length);
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript^0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|N|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|O|9|@]|A|@]|B|$]]|$2|E|4|F|6|7|8|P|9|@]|A|@]|B|$]]|$2|G|4|H|6|7|8|Q|9|@]|A|@]|B|$]]|$2|I|4|J|6|K|8|R|9|@]|A|@]|B|$L|M]]]]

Here is more "modern" complete code based on <a href="https://www.mkyong.com/java/how-to-decompress-files-from-a-zip-file/" rel="nofollow noreferrer">this</a> post but refactored (and using <a href="https://projectlombok.org/" rel="nofollow noreferrer"><code>Lombok</code></a>):

<pre><code>import lombok.var;
import lombok.val;

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipInputStream;

import static java.nio.file.Files.createDirectories;

public class UnZip
{
 public static void unZip(String sourceZipFile, String outputDirectory) throws IOException
 {
 val folder = new File(outputDirectory);
 createDirectories(folder.toPath());

 try (val zipInputStream = new ZipInputStream(new FileInputStream(sourceZipFile, Charset.forName("Cp437"))))
 {
 var nextEntry = zipInputStream.getNextEntry();

 while (nextEntry != null)
 {
 val fileName = nextEntry.getName();
 val newFile = new File(outputDirectory + File.separator + fileName);

 newFile.getParentFile().mkdirs();

 if(fileName.endsWith("/")){
 newFile.mkdirs();
 } else {
 writeFile(zipInputStream, newFile);
 }

 writeFile(zipInputStream, newFile);

 nextEntry = zipInputStream.getNextEntry();
 }

 zipInputStream.closeEntry();
 }
 }

 private static void writeFile(ZipInputStream inputStream, File file) throws IOException
 {
 val buffer = new byte[1024];
 file.createNewFile();
 try (val fileOutputStream = new FileOutputStream(file))
 {
 int length;
 while ((length = inputStream.read(buffer)) &gt; 0)
 {
 fileOutputStream.write(buffer, 0, length);
 }
 }
 }
}
</code></pre>

entityMap|blocks|key|93l7s|text|这是一个最简洁的、无库的Java+7%2B变体：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|a3uuk|public+static+void+unzip(InputStream+is,+Path+targetDir)+throws+IOException+{
++++targetDir+=+targetDir.toAbsolutePath();
++++try+(ZipInputStream+zipIn+=+new+ZipInputStream(is))+{
++++++++for+(ZipEntry+ze;+(ze+=+zipIn.getNextEntry())+!=+null;+)+{
++++++++++++Path+resolvedPath+=+targetDir.resolve(ze.getName()).normalize();
++++++++++++if+(!resolvedPath.startsWith(targetDir))+{
++++++++++++++++//+see:+https://snyk.io/research/zip-slip-vulnerability
++++++++++++++++throw+new+RuntimeException("Entry+with+an+illegal+path:+"+
++++++++++++++++++++++++%2B+ze.getName());
++++++++++++}
++++++++++++if+(ze.isDirectory())+{
++++++++++++++++Files.createDirectories(resolvedPath);
++++++++++++}+else+{
++++++++++++++++Files.createDirectories(resolvedPath.getParent());
++++++++++++++++Files.copy(zipIn,+resolvedPath);
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|ft2tk|The+The+The|528ko|在两个分支中都需要，因为zip文件并不总是包含所有父目录作为单独的条目，而可能只是为了表示空目录而包含它们。|d33sp|这段代码解决了|dni1|ZIP-slip漏洞|af8as|，则它将失败。如果某些ZIP条目位于|art89|..。这样的压缩不是使用常用工具创建的，很可能是手工创建的，以利用漏洞进行攻击。^0|0|0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|T|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|U|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|V|9|@]|A|@]|B|$]]|$2|J|4|K|6|7|8|W|9|@]|A|@]|B|$]]|$2|L|4|M|6|7|8|X|9|@]|A|@]|B|$]]|$2|N|4|O|6|7|8|Y|9|@]|A|@]|B|$]]|$2|P|4|Q|6|7|8|Z|9|@]|A|@]|B|$]]|$2|R|4|S|6|7|8|10|9|@]|A|@]|B|$]]]]

A most concise, library-free, Java 7+ variant:
<pre class="lang-java prettyprint-override"><code>public static void unzip(InputStream is, Path targetDir) throws IOException {
 targetDir = targetDir.toAbsolutePath();
 try (ZipInputStream zipIn = new ZipInputStream(is)) {
 for (ZipEntry ze; (ze = zipIn.getNextEntry()) != null; ) {
 Path resolvedPath = targetDir.resolve(ze.getName()).normalize();
 if (!resolvedPath.startsWith(targetDir)) {
 // see: https://snyk.io/research/zip-slip-vulnerability
 throw new RuntimeException(&quot;Entry with an illegal path: &quot; 
 + ze.getName());
 }
 if (ze.isDirectory()) {
 Files.createDirectories(resolvedPath);
 } else {
 Files.createDirectories(resolvedPath.getParent());
 Files.copy(zipIn, resolvedPath);
 }
 }
 }
}
</code></pre>
The <code>createDirectories</code> is needed in both branches because zip files not always contain all the parent directories as a separate entries, but might contain them only to represent empty directories.
The code addresses the <a href="https://snyk.io/research/zip-slip-vulnerability" rel="nofollow noreferrer">ZIP-slip vulnerability</a>, it fails if some ZIP entry would go outside of the <code>targetDir</code>. Such ZIPs are not created using the usual tools and are very likely hand-crafted to exploit the vulnerability.

entityMap|blocks|key|4pc0u|text|这是我用来解压缩包含多个目录的zip文件的代码。未使用外部库。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|8uug5|import+java.io.BufferedInputStream;
import+java.io.File;
import+java.io.FileOutputStream;
import+java.io.IOException;
import+java.util.Enumeration;
import+java.util.zip.ZipEntry;
import+java.util.zip.ZipFile;

public+class+UnzipFile
{
++public+static+void+main(String[]+args)+throws+IOException
++{
++++String+fileZip+=+"src/main/resources/abcd/abc.zip";
++++File+destDir+=+new+File("src/main/resources/abcd/abc");

++++try+(ZipFile+file+=+new+ZipFile(fileZip))
++++{
++++++Enumeration+zipEntries+=+file.entries();
++++++while+(zipEntries.hasMoreElements())
++++++{
++++++++ZipEntry+zipEntry+=+zipEntries.nextElement();
++++++++File+newFile+=+new+File(destDir,+zipEntry.getName());

++++++++//create+sub+directories
++++++++newFile.getParentFile().mkdirs();

++++++++if+(!zipEntry.isDirectory())
++++++++{
++++++++++try+(FileOutputStream+outputStream+=+new+FileOutputStream(newFile))
++++++++++{
++++++++++++BufferedInputStream+inputStream+=+new+BufferedInputStream(file.getInputStream(zipEntry));
++++++++++++while+(inputStream.available()+>+0)
++++++++++++{
++++++++++++++outputStream.write(inputStream.read());
++++++++++++}
++++++++++++inputStream.close();
++++++++++}
++++++++}

++++++}
++++}
++}

}|code-block|syntax|javascript^0|0^^$0|$]|1|@$2|3|4|5|6|7|8|H|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|I|9|@]|A|@]|B|$F|G]]]]

This is the code I used to unzip a zip file with multiple directories. No external libraries used.

<pre><code>import java.io.BufferedInputStream;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;

public class UnzipFile
{
 public static void main(String[] args) throws IOException
 {
 String fileZip = "src/main/resources/abcd/abc.zip";
 File destDir = new File("src/main/resources/abcd/abc");

 try (ZipFile file = new ZipFile(fileZip))
 {
 Enumeration&lt;? extends ZipEntry&gt; zipEntries = file.entries();
 while (zipEntries.hasMoreElements())
 {
 ZipEntry zipEntry = zipEntries.nextElement();
 File newFile = new File(destDir, zipEntry.getName());

 //create sub directories
 newFile.getParentFile().mkdirs();

 if (!zipEntry.isDirectory())
 {
 try (FileOutputStream outputStream = new FileOutputStream(newFile))
 {
 BufferedInputStream inputStream = new BufferedInputStream(file.getInputStream(zipEntry));
 while (inputStream.available() &gt; 0)
 {
 outputStream.write(inputStream.read());
 }
 inputStream.close();
 }
 }

 }
 }
 }

}
</code></pre>

Is there any sample code, how to particaly unzip folder from ZIP into my desired directory? I have read all files from folder "FOLDER" into byte array, how do I recreate from its file structure?

Java ZIP - how to unzip folder?

Java

 有没有什么示例代码，如何将ZIP中的文件夹解压到我想要的目录中？我已经将文件夹" folder“中的所有文件读取到字节数组中，如何从其文件结构重新创建？

问Java ZIP -如何解压文件夹？
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