如何对列表中不连续的元素进行混洗？
如何对列表中不连续的元素进行混洗？
提问于 2020-12-19 01:21:18
我在Python中有一个类似如下的列表：
["Apple", "Banana", "Coconut", "Durian", "Elderberry", "Fig", "Guava"]我的目标是打乱列表，以便某些元素被打乱，而其他元素则留在原来的地方。
例如，如果要对第0、1、2、4和6个元素进行混洗，则混洗的可能结果为：
["Elderberry", "Banana", "Apple", "Durian", "Guava", "Fig", "Coconut"]我该怎么做呢？random.shuffle似乎只支持单个对象/切片。单独对每个切片进行混洗只会在每个切片之间进行混洗，而不是在所有切片之间进行。
回答 4
Stack Overflow用户
发布于 2020-12-19 01:36:42
这就完成了任务--它返回列表的一个新副本，不过与random.shuffle()不同。
import random
def shuffle_some(source, shuffle_indices):
# Get the things to shuffle by the given indices
to_shuffle = [source[i] for i in shuffle_indices]
# and shuffle them.
random.shuffle(to_shuffle)
# Take a shallow copy of the source list so we can
# modify it...
shuffled = source[:]
# And iterate through pairs of indices in the `to_shuffle`
# list and the target indices to place them...
for i, source_index in enumerate(shuffle_indices):
# ... and put the shuffled items into place.
shuffled[source_index] = to_shuffle[i]
return shuffled
s = ["Apple", "Banana", "Coconut", "Durian", "Elderberry", "Fig", "Guava"]
for x in range(5):
print(shuffle_some(s, (0, 3, 4)))输出为例如
['Elderberry', 'Banana', 'Coconut', 'Apple', 'Durian', 'Fig', 'Guava']
['Durian', 'Banana', 'Coconut', 'Apple', 'Elderberry', 'Fig', 'Guava']
['Apple', 'Banana', 'Coconut', 'Durian', 'Elderberry', 'Fig', 'Guava']
['Apple', 'Banana', 'Coconut', 'Durian', 'Elderberry', 'Fig', 'Guava']
['Apple', 'Banana', 'Coconut', 'Elderberry', 'Durian', 'Fig', 'Guava']Stack Overflow用户
发布于 2020-12-19 01:30:45
可以把它想象成将一叠纸牌分成两堆--您想要洗牌的那一堆，以及您想要保留其顺序的那一堆。将纸牌从第二堆放在原来的位置，将第一堆洗牌，然后把洗好的牌放入剩余的空格中。
>>> import random
>>> fruits = ["Apple", "Banana", "Coconut", "Durian", "Elderberry", "Fig", "Guava"]
>>> shuffle_indices = (0, 1, 2, 4, 6)
>>> shuffled_items = random.sample([f for i, f in enumerate(fruits) if i in shuffle_indices], len(shuffle_indices))
>>> shuffled_fruits = [shuffled_items.pop() if i in shuffle_indices else f for i, f in enumerate(fruits)]
>>> shuffled_fruits
['Banana', 'Guava', 'Coconut', 'Durian', 'Apple', 'Fig', 'Elderberry']Stack Overflow用户
发布于 2020-12-19 01:30:38
你可以自己硬编码。
您可以提取要混洗的值，然后对这些值进行混洗。然后，将它们重新输入到原始文件中。
def my_shuffle(list_, *args):
shuffle_these = []
for i in args:
shuffle_these.append(list_[i])
random.shuffle(shuffle_these)
for integer, i in enumerate(list_):
if integer in args:
value = args.index(integer)
list_[integer] = shuffle_these[value]
return list_
print(my_shuffle([1, 2, 3, 4, 5, 6, 7], 1, 3, 6)) #this will shuffle the indices 1, 3, and 6结果：
[1, 4, 3, 2, 5, 6, 7]页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/65361245
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