如何处理奇数组项未定义的偏移错误？
如何处理奇数组项未定义的偏移错误？
提问于 2019-01-25 12:48:26
我有一个包含13项的数组，如下所示：
$skus = array(
"PK 800G",
"CH 800G",
"910G",
"400G",
"1.5KG",
"1KG",
"A 1KG",
"E 1KG",
"D 1KG",
"2 G.",
"ESSENCE",
"N 800G.",
"H 800 G"
);我的问题是，如果我在数组中有13项，下面的代码会给我错误：
(1/1) ErrorException
Undefined offset: 13但是如果我从数组中删除一项，并将其设置为"12“，那么它可以很好地工作。我确信这是因为循环。但是我想不出来。
$total = count($skus);
$skuKeys = array_keys($skus);
$iter = ceil($total / 4);
for ($n = 0; $n <= $iter; $n++) {
$row = ["G", "A"];
$row2 = ["", ""];
for ($j = $n*4; $j < 4 * ($n+1); $j++) {
if ($j == 2) {
$row = array_merge($row, ["RT + PK","","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
$row = array_merge($row, [$skuKeys[$j],"","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
}有谁能帮帮我吗？
谢谢。
回答 3
Stack Overflow用户
回答已采纳
发布于 2019-01-25 14:11:23
你有几个问题。首先，在计算$iter时，需要使用
$iter = floor(($total - 1) / 4);否则，对于4的倍数的$total，您将在循环中进行多次迭代，并且由于您在外部for循环中使用$n <= $iter，因此您需要使用floor而不是ceil，否则您将在循环中再次进行多次迭代。
您的第二个问题(也是导致错误消息的问题)是，在您的内部for循环中，您没有检查您是否仍然在数组的边界内。因此，在for之后，您需要添加对此的检查：
if ($j == $total) break;因此，您的代码应更改为：
$iter = floor(($total - 1) / 4);
for ($n = 0; $n <= $iter; $n++) {
$row = ["G", "A"];
$row2 = ["", ""];
for ($j = $n*4; $j < 4 * ($n+1); $j++) {
if ($j == $total) break;
if ($j == 2) {
$row = array_merge($row, ["RT + PK","","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
$row = array_merge($row, [$skuKeys[$j],"","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
}我怀疑您的代码中还存在其他问题(除非您在循环中对$row和$row2做了一些尚未向我们展示的操作)，因为您会在每次通过外部循环时覆盖$row和$row2的值。但是，这些修复将解决您当前的问题。
Stack Overflow用户
发布于 2019-01-25 12:54:34
实际上，您正在处理的array的长度比数组的长度小1。试试..。
$total = count($skus);
$skuKeys = array_keys($skus);
$iter = ceil($total / 4);
for ($n = 0; $n < $iter; $n++) {
$row = ["G", "A"];
$row2 = ["", ""];
for ($j = $n*4; $j < 4 * ($n+1); $j++) {
if ($j == 2) {
$row = array_merge($row, ["RT + PK","","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
$row = array_merge($row, [$skuKeys[$j],"","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
}Stack Overflow用户
发布于 2019-01-25 13:58:42
试试这个：
$skus = array(
"PK 800G",
"CH 800G",
"910G",
"400G",
"1.5KG",
"1KG",
"A 1KG",
"E 1KG",
"D 1KG",
"2 G.",
"ESSENCE",
"N 800G.",
"H 800 G"
);
$total = count($skus);
$skuKeys = array_keys($skus);
$iter = round($total / 4);
for ($n = 0; $n < $iter; $n++) {
$row = ["G", "A"];
$row2 = ["", ""];
for ($j = $n*4; $j < 4 * ($n+1); $j++) {
if ($j == 2) {
$row = array_merge($row, ["RT + PK","","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
$row = array_merge($row, [$skuKeys[$j],"","","","","",""]);
$row2 = array_merge($row2, ["TY", "LY", "YTD", "TY", "LY", "MTD", ""]);
}
}
var_dump($row);
var_dump($row2);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/54359077
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