blocks|key|1219362|text|我要在开始之前说，这可能不是最好的解决方案，在某些情况下可能不起作用，但你可以试一试，看看它是否能达到你想要的效果。我只是把它弄好了，所以里面可能有一些bug。它仍然会涉及一些代码，但它会让你的模型不知道你的视图。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1219363|您需要做的是创建一个扩展属性，该属性允许您在DataGrid上绑定Columns属性。这是我放在一起的一个例子。|1219364|using+System.Collections.ObjectModel;
using+System.Collections.Specialized;
using+System.Windows;
using+System.Windows.Controls;

public+static+class+DataGridExtension
{
++++public+static+ObservableCollection<DataGridColumn>+GetColumns(DependencyObject+obj)
++++{
++++++++return+(ObservableCollection<DataGridColumn>)obj.GetValue(ColumnsProperty);
++++}

++++public+static+void+SetColumns(DependencyObject+obj,+ObservableCollection<DataGridColumn>+value)
++++{
++++++++obj.SetValue(ColumnsProperty,+value);
++++}

++++public+static+readonly+DependencyProperty+ColumnsProperty+=++
+++++++++++DependencyProperty.RegisterAttached("Columns",
+++++++++++typeof(ObservableCollection<DataGridColumn>),
+++++++++++typeof(DataGridExtension),
+++++++++++new+UIPropertyMetadata+(new+ObservableCollection<DataGridColumn>(),
+++++++++++OnDataGridColumnsPropertyChanged));


++++private+static+void+OnDataGridColumnsPropertyChanged(
+++++++++++DependencyObject+d,
+++++++++++DependencyPropertyChangedEventArgs+e)
++++{
++++++++if+(d.GetType()+==+typeof(DataGrid))
++++++++{
++++++++++++DataGrid+myGrid+=+d+as+DataGrid;

++++++++++++ObservableCollection<DataGridColumn>+Columns+=+
+++++++++++++++++(ObservableCollection<DataGridColumn>)e.NewValue;

++++++++++++if(Columns+!=+null)
++++++++++++{
++++++++++++++++myGrid.Columns.Clear();

++++++++++++++++if+(Columns+!=+null+&&+Columns.Count+>+0)
++++++++++++++++{
++++++++++++++++++++foreach+(DataGridColumn+dataGridColumn+in+Columns)
++++++++++++++++++++{
++++++++++++++++++++++++myGrid.Columns.Add(dataGridColumn);
++++++++++++++++++++}
++++++++++++++++}


++++++++++++++++Columns.CollectionChanged+%2B=+delegate(object+sender,
+++++++++++++++++++++++++++++++++NotifyCollectionChangedEventArgs+args)
+++++++++++++++++++++{
+++++++++++++++++++++++if(args.NewItems+!=+null)
+++++++++++++++++++++++{
+++++++++++++++++++++++++foreach+(DataGridColumn+column+
++++++++++++++++++++++++++++++in+args.NewItems.Cast<DataGridColumn>())
+++++++++++++++++++++++++{
+++++++++++++++++++++++++++++myGrid.Columns.Add(column);
+++++++++++++++++++++++++}
+++++++++++++++++++++++}

+++++++++++++++++++++++if(args.OldItems+!=+null)
+++++++++++++++++++++++{
+++++++++++++++++++++++++foreach+(DataGridColumn+column+
+++++++++++++++++++++++++++++++++in+args.OldItems.Cast<DataGridColumn>())
+++++++++++++++++++++++++{
+++++++++++++++++++++++++++myGrid.Columns.Remove(column);
+++++++++++++++++++++++++}
+++++++++++++++++++++++}
++++++++++++++++++++};
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|1219365|然后像这样将它附加到您的列(其中DataGrid是视图模型上的ObservableCollection属性)|1219366|<Controls:DataGrid+AutoGenerateColumns="False"+
++++++++++++DataGridExtension.Columns="{Binding+Columns}"+/>|1219367|我不确定如果您开始添加和删除列，它会有多好的响应，但从我的基本测试来看，它似乎是有效的。祝好运!|1219368|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I'm going to preface this by saying it maybe isn't the best solution to be doing and may not work in some situations but you can give it a try and see if it will work for what you want. I just whipped this up so it may have some bugs in it. Its still going to involve some code, but it keeps your model from knowing about you view.

What you need to do is create an extension property that will allow you to bind the Columns property on the DataGrid. Here is an example that I put together.

<pre><code>using System.Collections.ObjectModel;
using System.Collections.Specialized;
using System.Windows;
using System.Windows.Controls;

public static class DataGridExtension
{
 public static ObservableCollection&lt;DataGridColumn&gt; GetColumns(DependencyObject obj)
 {
 return (ObservableCollection&lt;DataGridColumn&gt;)obj.GetValue(ColumnsProperty);
 }

 public static void SetColumns(DependencyObject obj, ObservableCollection&lt;DataGridColumn&gt; value)
 {
 obj.SetValue(ColumnsProperty, value);
 }

 public static readonly DependencyProperty ColumnsProperty = 
 DependencyProperty.RegisterAttached("Columns",
 typeof(ObservableCollection&lt;DataGridColumn&gt;),
 typeof(DataGridExtension),
 new UIPropertyMetadata (new ObservableCollection&lt;DataGridColumn&gt;(),
 OnDataGridColumnsPropertyChanged));


 private static void OnDataGridColumnsPropertyChanged(
 DependencyObject d,
 DependencyPropertyChangedEventArgs e)
 {
 if (d.GetType() == typeof(DataGrid))
 {
 DataGrid myGrid = d as DataGrid;

 ObservableCollection&lt;DataGridColumn&gt; Columns = 
 (ObservableCollection&lt;DataGridColumn&gt;)e.NewValue;

 if(Columns != null)
 {
 myGrid.Columns.Clear();

 if (Columns != null &amp;&amp; Columns.Count &gt; 0)
 {
 foreach (DataGridColumn dataGridColumn in Columns)
 {
 myGrid.Columns.Add(dataGridColumn);
 }
 }


 Columns.CollectionChanged += delegate(object sender,
 NotifyCollectionChangedEventArgs args)
 {
 if(args.NewItems != null)
 {
 foreach (DataGridColumn column 
 in args.NewItems.Cast&lt;DataGridColumn&gt;())
 {
 myGrid.Columns.Add(column);
 }
 }

 if(args.OldItems != null)
 {
 foreach (DataGridColumn column 
 in args.OldItems.Cast&lt;DataGridColumn&gt;())
 {
 myGrid.Columns.Remove(column);
 }
 }
 };
 }
 }
 }
}
</code></pre>

Then you attach it to you DataGrid like this (Where columns is the an ObservableCollection property on your view model)

<pre><code>&lt;Controls:DataGrid AutoGenerateColumns="False" 
 DataGridExtension.Columns="{Binding Columns}" /&gt;
</code></pre>

I'm not sure how well it is going to respond if you start adding and remove columns, but it seems to work from my basic testing. Good Luck!

blocks|key|1005044|text|我想扩展前面的示例(答案)，可以在event+CollectionChanged上订阅和取消订阅。Link+on+my+answer+in+related+theme。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1005045|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/15549193/is-it-possible-to-get-dynamic-columns-on-wpf-datagrid-in-mvvm-pattern/19025694#19025694^0|1D|Y|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

I would like to extend the previous example (answer) the ability to subscribe and unsubscribe on event CollectionChanged. <a href="https://stackoverflow.com/questions/15549193/is-it-possible-to-get-dynamic-columns-on-wpf-datagrid-in-mvvm-pattern/19025694#19025694">Link on my answer in related theme</a>.

blocks|key|1219436|text|由于有类似的问题，我不想添加另一个依赖属性。我的解决方法是在DataTable中组织要在DataGrid中显示的数据，并将DataGrid+ItemSource属性绑定到此DataTable+(当然，将AutoGenerateColumns设置为true)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1219437|它工作得很好，DataGrids似乎对DataTable作为源代码很满意。|1219438|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Having a similar problem, I did not want to add another dependency property.
My workaround was to organise the data to display in the DataGrid in a DataTable and bind the DataGrid ItemSource property to this DataTable (with of course AutoGenerateColumns set to true).

It works well, DataGrids seem happy with DataTable as source.

I am searching about how to create the columns of the DataGrid from the ToolKit dynamic in MvvM way. But looks like it is impossible !

Is there some one that had to do the samething ?

there is no need to create a usercontrol or another control that comes from DataGrid, I just want to set de ItemSource of the grid to my custom object and in some point I want to define the columns of the grid in runtime dynamic based in the kind of the object.

Is that possible ?

cheers

WPF MvvM DataGrid Dynamic Columns

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在搜索如何以MvvM方式从ToolKit动态创建DataGrid的列。但是看起来这是不可能的！有没有人不得不做同样的事情？不需要创建用户控件或其他来自DataGrid的控件，我只想将网格的de ItemSource设置为我的自定义对象，并且在某些情况下，我想基于对象的类型在运行时动态定义网格的列。这有可能吗？干杯

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