在Python上使用if语句和append时出现的问题
在Python上使用if语句和append时出现的问题
提问于 2020-12-12 10:01:03
我对编码比较陌生，我对我的代码为什么不能工作感到非常困惑，它看起来应该工作，但它不是。它首先询问所需的座位数量，然后询问那里的名字，然后是食物选择。它会附加名字，但只会附加第一个食物选项，之后就不会添加任何东西了。我没有收到任何错误。
下面是我的代码：
people = []
working = False
seatNum = input("How many seats do you need: ")
while (not seatNum.isnumeric()):
print("Invalid")
seatNum = input("How many seats do you need: ")
print("Mince pie = 1, Chocolate coins = 2, Apple pie = 3")
seatNum = int(seatNum)
for i in range(seatNum):
Nam = input("Enter name: ")
people.append(Nam)
choice = input("Enter your choice: ")
while (working == False):
while (not choice.isnumeric()):
print("Invalid")
choice = input("Enter your choice: ")
choice = int(choice)
if choice == 1 or choice == 2 or choice == 3:
working = True
else:
print("Enter number between 1-3")
choice = input("Enter your choice: ")
if choice == 1:
people.append("Mince Pie")
elif choice == 2:
people.append("Chocolate coins")
elif choice == 3:
people.append("Apple pie")
print(people)这就是我的代码，虽然非常混乱，但它还没有完成。下面是输出：
How many seats do you need: 3
Mince pie = 1, Chocolate coins = 2, Apple pie = 3
Enter name: a
Enter your choice: 1
Enter name: b
Enter your choice: 2
Enter name: c
Enter your choice: 3
['a', 'Mince Pie', 'b', 'c']下面是所需的输出：
How many seats do you need: 3
Mince pie = 1, Chocolate coins = 2, Apple pie = 3
Enter name: a
Enter your choice: 1
Enter name: b
Enter your choice: 2
Enter name: c
Enter your choice: 3
['a', 'Mince Pie', 'b', 'Chocolate coins', 'c', 'Apple pie']任何和所有的帮助都是感激的。提前感谢
塔莉亚。
回答 3
Stack Overflow用户
发布于 2020-12-12 10:05:18
while (working == False):在第一次循环之后，这个while循环将不会为guests运行，因为当时working被设置为True，并且没有被重置。
choice = int(choice)这部分只发生在while循环内部，所以在第一个循环之后不会发生在guests中。
if choice == 1:因为choice仍然是一个字符串，所以这些比较总是失败。
Stack Overflow用户
发布于 2020-12-12 10:14:27
运行‘While(working == False)’循环之后。在循环中设置working = True。下一次为下一个人运行循环时，working仍然等于True。因此循环将不会运行。尝试以下部分代码：
#Add your original code
for i in range(seatNum):
Nam = input("Enter name: ")
people.append(Nam)
choice = input("Enter your choice: ")
working = False #This statement is what I added
while (working == False):
while (not choice.isnumeric()):
print("Invalid")
choice = input("Enter your choice: ")
choice = int(choice)
#Continue your code normally这样，每次循环运行时，工作变量都将为False，并且循环将能够运行。
Stack Overflow用户
发布于 2020-12-12 11:18:55
if choice == 1 or choice == 2 or choice == 3:
working = True这就是导致问题的原因。一旦程序看到选项等于这些数字中的一个，它就会将working更改为True，并停止附加选项。
people = []
seatNum = input("How many seats do you need: ")
while seatNum.isnumeric() == False:
print("Invalid")
seatNum = input("How many seats do you need: ")
seatNum = int(seatNum)
print("Mince pie = 1, Chocolate coins = 2, Apple pie = 3")
while seatNum*2 != len(people):
Nam = input('Enter Name: ')
people.append(Nam)
choice = input('What is your choice: ')
while choice.isnumeric() == False:
print('Invalid')
choice = input('What is your choice: ')
choice = int(choice)
if choice == 1:
people.append("Mince Pie")
elif choice == 2:
people.append("Chocolate coins")
elif choice == 3:
people.append("Apple pie")
print(people)我去掉了工作变量，以使代码的逻辑运行得更好。while循环的逻辑一直运行到len(people)为双倍seatNum，因为每个人都有一个选择。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/65260849
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