Warning:'sendSynchronousRequest(_:returningResponse:)‘在iOS 9.0中已弃用:使用NSURLSession dataTaskWithRequest:completionHandler:
urlData = try NSURLConnection.sendSynchronousRequest(request, returningResponse:&response)
有关于如何摆脱这个警告的想法吗?我刚刚从Swift 1.2升级到Swift 2
更新: Fonix被标记为我的最佳答案。如果你想添加一个try语句,我将他的回答修改如下:
urlData = try NSURLSession.dataTaskWithRequest(<#request: NSURLRequest#>, completionHandler: <#((NSData!, NSURLResponse!, NSError!) -> Void)?##(NSData!, NSURLResponse!, NSError!) -> Void#>)
发布于 2015-09-18 17:51:28
请使用NSURLSession
,如下所示:
对于Objective-C
NSURLSession *session = [NSURLSession sharedSession];
[[session dataTaskWithURL:[NSURL URLWithString:londonWeatherUrl]
completionHandler:^(NSData *data,
NSURLResponse *response,
NSError *error) {
// handle response
}] resume];
对斯威夫特来说
var request = NSMutableURLRequest(URL: NSURL(string: "YOUR URL"))
var session = NSURLSession.sharedSession()
request.HTTPMethod = "POST"
var params = ["username":"username", "password":"password"] as Dictionary<String, String>
var err: NSError?
request.HTTPBody = NSJSONSerialization.dataWithJSONObject(params, options: nil, error: &err)
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
var task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
println("Response: \(response)")})
task.resume()
发布于 2016-05-21 00:56:21
当你实际需要同步请求阻塞当前线程执行时,我写了下面的解决方案。我使用这段代码在复杂的解决方案中从NSURLConnection
迁移到NSURLSession
,其中是一个相当麻烦的,只需更改为异步方法。使用此解决方案,迁移只是方法名称替换。
注意:如果您有一个简单的案例,请使用接受的答案。
- (NSData *)sendSynchronousRequest:(NSURLRequest *)request returningResponse:(NSURLResponse **)response error:(NSError **)error
{
NSError __block *err = NULL;
NSData __block *data;
BOOL __block reqProcessed = false;
NSURLResponse __block *resp;
[[[NSURLSession sharedSession] dataTaskWithRequest:request completionHandler:^(NSData * _Nullable _data, NSURLResponse * _Nullable _response, NSError * _Nullable _error) {
resp = _response;
err = _error;
data = _data;
reqProcessed = true;
}] resume];
while (!reqProcessed) {
[NSThread sleepForTimeInterval:0.02];
}
if (response != nil)
*response = resp;
if (error != nil)
*error = err;
return data;
}
用法(简单地将NSURLConnection
替换为此方法):
//NSData *data = [NSURLConnection sendSynchronousRequest:theRequest returningResponse:&resp error:&err];
NSData *data = [self sendSynchronousRequest:theRequest returningResponse:&resp error:&err];
发布于 2017-05-20 00:47:53
如果你需要阻塞当前线程(就像Mike Keskinov的答案),最好使用gdc信号量,而不是执行NSThread :0。例如:
dispatch_semaphore_t semaphore = dispatch_semaphore_create(0);
NSURLSession *session = [NSURLSession sharedSession];
[[session dataTaskWithURL:[NSURL URLWithString:londonWeatherUrl]
completionHandler:^(NSData *data,
NSURLResponse *response,
NSError *error) {
// handle response
dispatch_semaphore_signal(semaphore);
}] resume];
dispatch_semaphore_wait(semaphore, DISPATCH_TIME_FOREVER);
和Swift (在5.0上测试):
let semaphore = DispatchSemaphore(value:0)
URLSession.shared.dataTask(with: serverUrl) { (httpData, response, error) in
// handle response
semaphore.signal()
}.resume()
semaphore.wait()
https://stackoverflow.com/questions/32643207
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