问用c#在emgucv中获取图像角度的NaN

EN

 Image<Gray, byte> imgout = imgInput.Convert<Gray, byte>().Not().ThresholdBinary(new 
 Gray(50), new Gray(255));
 VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
 Mat hier = new Mat();

CvInvoke.FindContours(imgout, contours, hier, Emgu.CV.CvEnum.RetrType.External, Emgu.CV.CvEnum.ChainApproxMethod.ChainApproxSimple);
     for (int i = 0; i <= 1; i++)
     {
        Rectangle rect = CvInvoke.BoundingRectangle(contours[i]);
        RotatedRect box = CvInvoke.MinAreaRect(contours[i]);
        PointF[] Vertices = box.GetVertices();
        PointF point = box.Center;
        PointF edge1 = new PointF(Vertices[1].X - Vertices[0].X, 
        Vertices[1].Y - Vertices[0].Y);
        PointF edge2 = new PointF(Vertices[2].X - Vertices[1].X,Vertices[2].Y - Vertices[1].Y);                     
        double edge1Magnitude = Math.Sqrt(Math.Pow(edge1.X, 2) + Math.Pow(edge1.Y, 2));
        double edge2Magnitude = Math.Sqrt(Math.Pow(edge2.X, 2) + Math.Pow(edge2.Y, 2));
        PointF primaryEdge = edge1Magnitude > edge2Magnitude ? edge1 : edge2;
        PointF reference = new PointF(Vertices[1].X, Vertices[0].Y);
        double thetaRads = Math.Acos((primaryEdge.X * reference.X) + (primaryEdge.Y * reference.Y))/(edge1Magnitude* edge2Magnitude);
        double thetaDeg = thetaRads * 180 / Math.PI;
    }