blocks|key|764109|text|这是因为pushd是bash中的一个内置函数。因此它与PATH变量无关，而且/bin/sh+(+make默认使用它)也不支持它。您可以通过设置SHELL来更改它(尽管它不会直接工作(test1))。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|764110|相反，您可以通过bash+-c+"..."运行所有命令。这将使命令(包括pushd/popd+)在bash环境(test2)中运行。|offset|length|style|CODE|764111|SHELL+=+/bin/bash

test1:
++++++++@echo+before
++++++++@pwd
++++++++@pushd+/tmp
++++++++@echo+in+/tmp
++++++++@pwd
++++++++@popd
++++++++@echo+after
++++++++@pwd

test2:
++++++++@/bin/bash+-c+"echo+before;\
++++++++pwd;+\
++++++++pushd+/tmp;+\
++++++++echo+in+/tmp;+\
++++++++pwd;+\
++++++++popd;+\
++++++++echo+after;+\
++++++++pwd;"|code-block|syntax|javascript|764112|当运行make+test1和make+test2时，它提供了以下内容：|764113|prompt>make+test1
before
/download/2011/03_mar
make:+pushd:+Command+not+found
make:+***+[test1]+Error+127
prompt>make+test2
before
/download/2011/03_mar
/tmp+/download/2011/03_mar
in+/tmp
/tmp
/download/2011/03_mar
after
/download/2011/03_mar
prompt>|764114|对于test1，即使将bash用作shell，规则中的每个命令/行都是单独运行的，因此pushd命令在与popd不同的shell中运行。|764115|entityMap^0|0|8|D|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Y|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

This is because pushd is a builtin function in bash. So it is not related to the PATH variable and also it is not supported by /bin/sh (which is used by default by make. You can change that by setting SHELL (although it will not work directly (test1)).

You can instead run all the commands through <code>bash -c "..."</code>. That will make the commands, including pushd/popd, run in a bash environment (test2).

<pre><code>SHELL = /bin/bash

test1:
 @echo before
 @pwd
 @pushd /tmp
 @echo in /tmp
 @pwd
 @popd
 @echo after
 @pwd

test2:
 @/bin/bash -c "echo before;\
 pwd; \
 pushd /tmp; \
 echo in /tmp; \
 pwd; \
 popd; \
 echo after; \
 pwd;"
</code></pre>

When running make test1 and make test2 it gives the following:

<pre><code>prompt&gt;make test1
before
/download/2011/03_mar
make: pushd: Command not found
make: *** [test1] Error 127
prompt&gt;make test2
before
/download/2011/03_mar
/tmp /download/2011/03_mar
in /tmp
/tmp
/download/2011/03_mar
after
/download/2011/03_mar
prompt&gt;
</code></pre>

For test1, even though bash is used as a shell, each command/line in the rule is run by itself, so the pushd command is run in a different shell than the popd.

blocks|key|764547|text|sudo+dpkg-reconfigure+dash+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|764548|然后选择no。|unstyled|offset|length|style|CODE|764549|entityMap^0|0|4|2|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>sudo dpkg-reconfigure dash 
</code></pre>

Then select <code>no</code>.

blocks|key|764172|text|您的shell+(/bin/sh)正在尝试查找'pushd‘。但是它找不到它，因为'pushd'，'popd‘和其他类似的命令都是内置在bash中的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|764173|使用Bash+(/bin/bash)启动脚本，而不是像现在这样使用Sh，它将会工作|764174|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Your shell (/bin/sh) is trying to find 'pushd'. But it can't find it because 'pushd','popd' and other commands like that are build in bash.

Launch you script using Bash (/bin/bash) instead of Sh like you are doing now, and it will work

blocks|key|979927|text|这应该能起到作用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|979928|(+cd+dirname+;+pwd+);+pwd|code-block|syntax|javascript|979929|括号启动了一个新的子cd，因此shell仅更改子shell中的目录，并且括号中它后面的任何命令都将在该文件夹中运行。一旦您退出括号，您就回到了以前所在的位置。|offset|length|style|CODE|979930|entityMap^0|0|0|A|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This ought to do the trick:

<pre><code>( cd dirname ; pwd ); pwd
</code></pre>

The parentheses start a new child shell, thus the <code>cd</code> changes the directory within the child only, and any command after it within the parentheses will run in that folder. Once you exit the parentheses you are back in wherever you were before..

blocks|key|979718|text|从其他响应中合成：pushd是特定于bash的，而您正在使用另一个POSIX+shell。对于需要不同目录的部分，有一个简单的解决方法，可以使用单独的shell，因此只需尝试将其更改为：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|979719|test+-z+gen+%7C%7C+mkdir+-p+gen+\
+&&+(+cd+$(CURRENT_DIRECTORY)/genscript+>+/dev/null+\
+&&+perl+genmakefile.pl+\
+&&+mv+Makefile+../gen/+)+\
+&&+echo+""+>+$(CURRENT_DIRECTORY)/gen/SvcGenLog|code-block|syntax|javascript|979720|(我将长路径替换为变量扩展。我可能是makefile中的一个，它明显扩展到当前目录)。|979721|既然您是从make运行它，我可能也会用make规则替换测试。只是|979722|gen/SvcGenLog+:
++++mkdir+-p+gen
++++cd+genscript+>+/dev/null+\
+++++&&+perl+genmakefile.pl+\
+++++&&+mv+Makefile+../gen/+\
++++echo+""+>+gen/SvcGenLog|979723|(删除了当前目录前缀；您在某些情况下使用了相对路径)，而不是仅仅使规则依赖于gen/SvcGenLog。它的可读性会更好一些，你也可以让它依赖于genscript/genmakefile.pl，所以如果你修改这个脚本，gen中的Makefile就会重新生成。当然，如果有任何其他东西影响Makefile的内容，您也可以使规则依赖于此。|979724|entityMap^0|9|5|0|0|0|0|0|12|D|20|O|31|3|36|8|3Z|8|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|T|$]]

Synthesizing from the other responses: <code>pushd</code> is bash-specific and you are make is using another POSIX shell. There is a simple workaround to use separate shell for the part that needs different directory, so just try changing it to:

<pre><code>test -z gen || mkdir -p gen \
 &amp;&amp; ( cd $(CURRENT_DIRECTORY)/genscript &gt; /dev/null \
 &amp;&amp; perl genmakefile.pl \
 &amp;&amp; mv Makefile ../gen/ ) \
 &amp;&amp; echo "" &gt; $(CURRENT_DIRECTORY)/gen/SvcGenLog
</code></pre>

(I substituted the long path with a variable expansion. I probably is one in the makefile and it clearly expands to the current directory).

Since you are running it from make, I would probably replace the test with a make rule, too. Just

<pre><code>gen/SvcGenLog :
 mkdir -p gen
 cd genscript &gt; /dev/null \
 &amp;&amp; perl genmakefile.pl \
 &amp;&amp; mv Makefile ../gen/ \
 echo "" &gt; gen/SvcGenLog
</code></pre>

(dropped the current directory prefix; you were using relative path at some points anyway)
And than just make the rule depend on <code>gen/SvcGenLog</code>. It would be a bit more readable and you can make it depend on the <code>genscript/genmakefile.pl</code> too, so the <code>Makefile</code> in <code>gen</code> will be regenerated if you modify the script. Of course if anything else affects the content of the <code>Makefile</code>, you can make the rule depend on that too.

blocks|key|979785|text|请注意，make文件执行的每一行都是在其自己的shell中运行的。如果您更改了目录，则不会影响后续行。所以你可能对pushd和popd没什么用处，你的问题恰恰相反，那就是让目录在你需要的时候一直保持改变！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|979786|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Note that each line executed by a make file is run in its own shell anyway. If you change directory, it won't affect subsequent lines. So you probably have little use for pushd and popd, your problem is more the opposite, that of getting the directory to stay changed for as long as you need it!

blocks|key|764518|text|运行"apt+install+bash“，它将安装您需要的所有内容，并且该命令将生效|type|unstyled|depth|inlineStyleRanges|entityRanges|data|764519|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Run "apt install bash"
It will install everything you need and the command will work

I am doing the following inside a make file 

<pre><code>pushd %dir_name%
</code></pre>

and i get the following error

<pre><code>/bin/sh : pushd : not found
</code></pre>

Can someone please tell me why this error is showing up ?
I checked my $PATH variable and it contains /bin so I don't think that is causing a problem.

/bin/sh: pushd: not found

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在make文件中执行以下操作pushd %dir_name%我得到了下面的错误/bin/sh : pushd : not found有人能告诉我为什么会出现这个错误吗？我检查了我的$PATH变量，它包含/bin，所以我不认为这会导致问题。

问/bin/sh: pushd:未找到
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