如何在python中使用break来结束while循环？
如何在python中使用break来结束while循环？
提问于 2021-05-09 11:03:34
我在这里写了一个循环，询问用户是否想重复一段指令。并想给用户三次尝试来选择他想要的(是/否)，如果他没有结束循环。这是我的代码：
# Ask for repeating
i = 0
def question():
global i
while True:
print("Give another try?")
answer = input("(Y/N): ")
answer = answer.upper()
if answer == 'Y':
main()
elif answer == 'N':
print("Thank you for participating")
break # here it works when 'n' is typed
else: # i count how much the while loop id repeated
if (i < 2):
i += 1
question()
else: # else is executed when i == 2
print("don't Play with us!!")
break # here it doesn't work.我需要帮助。
回答 2
Stack Overflow用户
回答已采纳
发布于 2021-05-09 11:11:27
x = True
i = 0
def question():
# Ask for repeating
global i
global x
while x is True:
print("Give another try?")
answer ='a'
answer = answer.upper()
if answer == 'Y':
pass
elif answer == 'N':
print("Thank you for participating")
break # here it works when 'n' is typed
else: # i count how much the while loop id repeated
if (i < 2):
i += 1
question()
else: # else is executed when i == 2
print("don't Play with us!!")
x = False # here it doesn't work.Stack Overflow用户
发布于 2021-05-09 11:19:38
在最后一个else块之外添加另一个分隔符。你的代码应该是
i = 0
def question():
global i
while True:
print("Give another try?")
answer = input("(Y/N): ")
answer = answer.upper()
if answer == 'Y':
main()
elif answer == 'N':
print("Thank you for participating")
break # here it works when 'n' is typed
else: # i count how much the while loop id repeated
if (i < 2):
i += 1
question()
else: # else is executed when i == 2
print("don't Play with us!!")
break # here it doesn't work.
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原文链接：
https://stackoverflow.com/questions/67453942
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