我触发了一个选择压缩文件的意图,在onActivityResult中,它为我提供了一个内容URI。例如::(content://com.android.providers.downloads.documents/document/197).选择的文件来自下载文件夹。谁能解释一下,如何查询内容解析器以获得文件路径?谢谢。
Already tried code :-
Cursor cursor = getActivity().getContentResolver()
.query(contentUri, null, null, null, null);
try {
if (cursor != null && cursor.moveToFirst()) {
String path=cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
Log.i(TAG, "path Name: " + path);
}
// NOTE :: Here I am getting the file name, But i want the file path.
} finally {
cursor.close();
}发布于 2019-10-24 14:12:34
我尝试了很多方法来从下载文件夹中选择的文件中检索文件路径。从android Q开始,google建议使用SAF(Storage Access Framework)来获取用户的数据。我们不能使用Environment.getExternalStoragePublicDirectory()从android q及更高版本获取文件路径。
对于android Q及更高版本,您可以按照以下步骤操作。
1)从您要触发的activity或fragment开始intent。
例如:
public void performFileSearch() { //from developer docs
// ACTION_OPEN_DOCUMENT is the intent to choose a file via the system's file
// browser.
Intent intent = new Intent(Intent.ACTION_OPEN_DOCUMENT);
// Filter to only show results that can be "opened", such as a
// file (as opposed to a list of contacts or timezones)
intent.addCategory(Intent.CATEGORY_OPENABLE);
// Filter to show only images, using the image MIME data type.
// If one wanted to search for ogg vorbis files, the type would be "audio/ogg".
// To search for all documents available via installed storage providers,
// it would be "*/*".
intent.setType("application/pdf"); // MIME type for what file you required
startActivityForResult(intent, READ_REQUEST_CODE);
}2)然后,结果将以您的活动或片段的onActivityResult形式出现
@Override
public void onActivityResult(int requestCode, int resultCode,
Intent resultData) { // from developer docs
// The ACTION_OPEN_DOCUMENT intent was sent with the request code
// READ_REQUEST_CODE. If the request code seen here doesn't match, it's the
// response to some other intent, and the code below shouldn't run at all.
if (requestCode == READ_REQUEST_CODE && resultCode == Activity.RESULT_OK) {
// The document selected by the user won't be returned in the intent.
// Instead, a URI to that document will be contained in the return intent
// provided to this method as a parameter.
// Pull that URI using resultData.getData().
Uri uri = null;
if (resultData != null) {
uri = resultData.getData();
Log.i(TAG, "Uri: " + uri.toString());
processWithUriToGetPath(uri);
}
}
}从uri中提取数据(注意:对于图像、视频和音频,您可以参考developer document.Since没有找到任何适合文件的文档,给出了这个例子)。
private void processWithUriToGetPath(Uri contentUri) {
//Use content Resolver to get the input stream that it holds the data and copy that in a temp file of your app file directory for your references
File selectedFile = new File(getActivity().getFilesDir(), "your file name"); //your app file dir or cache dir you can use
InputStream in = getActivity().getContentResolver().openInputStream(contentUri);
OutputStream out = new FileOutputStream(selectedFile);
try {
byte[] buf = new byte[1024];
int len;
if (in != null) {
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
out.close();
in.close();
} catch (IOException ie) {
ie.printStackTrace();
}
//after this you will get file from the selected file and you can do
whatever with your wish.
// Hope it helps...
}https://stackoverflow.com/questions/58425517
复制相似问题