ES6 : mailchimp api的对象重构
ES6 : mailchimp api的对象重构
提问于 2019-03-06 08:58:06
我想在数组和另一个对象的基础上构造一个对象。
目标是将我的用户兴趣发送到mailchimp api，为此，我得到了：
//Array of skills for one user
const skillsUser1 = ["SKILL1", "SKILL3"]
//List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
'SKILL1': 'list_id_1',
'SKILL2': 'list_id_2',
'SKILL3': 'list_id_3',
}
//Mapping of user skill to all skills
const outputSkills = skillsUser1.map((skill) => skillsMailchimpId[skill]);
console.log(outputSkills);问题是之后，outputSkill给我一个数组：
["ID1", "ID3"]但是mailchimp api need，所以我需要的是：：
{ "list_id_1": true,
"list_id_2": false, //or empty
"list_id_3" : true
}回答 1
Stack Overflow用户
回答已采纳
发布于 2019-03-06 09:27:38
一种简单的方法是这样(参见代码中的注释以获得解释)：
// Array of skills for one user
const skillsUser1 = ["SKILL1", "SKILL3"]
// List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
'SKILL1': 'list_id_1',
'SKILL2': 'list_id_2',
'SKILL3': 'list_id_3',
}
// Create an output object
const outputSkills = {};
// Use `Object.entries` to transform `skillsMailchimpId` to array
Object.entries(skillsMailchimpId)
// Use `.forEach` to add properties to `outputSkills`
.forEach(keyValuePair => {
const [key, val] = keyValuePair;
outputSkills[val] = skillsUser1.includes(key);
});
console.log(outputSkills);
基本思想是在skillsMailchimpId上循环而不是在skillsUser上循环。
但这并不是非常动态的。对于您的生产代码，您可能希望对其进行重构以使其更加灵活。
// Array of skills for one user
const skillsUser1 = ["SKILL1", "SKILL3"]
// List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
'SKILL1': 'list_id_1',
'SKILL2': 'list_id_2',
'SKILL3': 'list_id_3',
}
// Use `Object.entries` to transform `skillsMailchimpId` to array
const skillsMailchimpIdEntries = Object.entries(skillsMailchimpId);
const parseUserSkills = userSkills => {
// Create an output object
const outputSkills = {};
// Use `.forEach` to add properties to `outputSkills`
skillsMailchimpIdEntries.forEach(([key, val]) => {
outputSkills[val] = userSkills.includes(key);
});
return outputSkills;
}
// Now you can use the function with any user
console.log(parseUserSkills(skillsUser1));
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原文链接：
https://stackoverflow.com/questions/55013909
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