blocks|key|844289|text|这段代码将为您拆分它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844290|list($whole,+$decimal)+=+explode('.',+$your_number);|code-block|syntax|javascript|844291|其中$whole是整数，$decimal是小数点后的数字。|844292|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This code will split it up for you:

<pre><code>list($whole, $decimal) = explode('.', $your_number);
</code></pre>

where $whole is the whole number and $decimal will have the digits after the decimal point.

blocks|key|844649|text|floor()方法不适用于负数。每次都是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844650|$num+=+5.7;
$whole+=+(int)+$num;++//+5
$frac++=+$num+-+$whole;++//+.7|code-block|syntax|javascript|844651|...also适用于底片(相同的代码，不同的数字)：|844652|$num+=+-5.7;
$whole+=+(int)+$num;++//+-5
$frac++=+$num+-+$whole;++//+-.7|844653|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The floor() method doesn't work for negative numbers. This works every time:

<pre><code>$num = 5.7;
$whole = (int) $num; // 5
$frac = $num - $whole; // .7
</code></pre>

...also works for negatives (same code, different number):

<pre><code>$num = -5.7;
$whole = (int) $num; // -5
$frac = $num - $whole; // -.7
</code></pre>

blocks|key|628671|text|只是为了有所不同:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|628672|list($whole,+$decimal)+=+sscanf(1.5,+'%25d.%25d');|code-block|syntax|javascript|628673|CodePad。|offset|length|628674|作为一个额外的好处，它只会在两端都由数字组成的情况下拆分。|628675|entityMap|0|LINK|mutability|MUTABLE|url|http://codepad.org/myLIEIsr^0|0|0|0|7|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Just to be different :)

<pre><code>list($whole, $decimal) = sscanf(1.5, '%d.%d');
</code></pre>

<a href="http://codepad.org/myLIEIsr" rel="noreferrer">CodePad</a>.

As an added benefit, it will only split where both sides consist of digits.

blocks|key|628925|text|快捷方式(使用floor和fmod)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|628926|$var+=+"1.25";
$whole+=+floor($var);+++++//+1
$decimal+=+fmod($var,+1);+//0.25|code-block|syntax|javascript|628927|然后将$decimal与0、.25、.5或.75进行比较|628928|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

a short way (use floor and fmod)

<pre><code>$var = "1.25";
$whole = floor($var); // 1
$decimal = fmod($var, 1); //0.25
</code></pre>

then compare $decimal to 0, .25, .5, or .75

blocks|key|844478|text|将其转换为int并减去|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844479|$integer+=+(int)$your_number;
$decimal+=+$your_number+-+$integer;|code-block|syntax|javascript|844480|或者只是为了获取小数以进行比较|844481|$decimal+=+$your_number+-+(int)$your_number|844482|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Cast it as an int and subtract

<pre><code>$integer = (int)$your_number;
$decimal = $your_number - $integer;
</code></pre>

Or just to get the decimal for comparison

<pre><code>$decimal = $your_number - (int)$your_number
</code></pre>

blocks|key|844389|text|还有一个可以使用的fmod函数:+fmod($my_var，1)将返回相同的结果，但有时会有很小的舍入误差。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844390|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

There's a fmod function too, that can be used :
fmod($my_var, 1)
will return the same result, but sometime with a small round error.

blocks|key|628767|text|这是我使用的方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|628768|$float+=+4.3;++++

$dec+=+ltrim(($float+-+floor($float)),"0.");+//+result+.3|code-block|syntax|javascript|628769|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is the way which I use:

<pre><code>$float = 4.3; 

$dec = ltrim(($float - floor($float)),"0."); // result .3
</code></pre>

blocks|key|628875|text|布拉德·克里斯蒂的方法本质上是正确的，但它可以写得更简洁。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|628876|function+extractFraction+($value)+
{
++++$fraction+++=+$value+-+floor+($value);
++++if+($value+<+0)
++++{
++++++++$fraction+*=+-1;
++++}

++++return+$fraction;
}|code-block|syntax|javascript|628877|这相当于他的方法，但更短，希望更容易理解。|628878|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Brad Christie's method is essentially correct but it can be written more concisely. 

<pre><code>function extractFraction ($value) 
{
 $fraction = $value - floor ($value);
 if ($value &lt; 0)
 {
 $fraction *= -1;
 }

 return $fraction;
}
</code></pre>

This is equivalent to his method but shorter and hopefully easier to understand as a result.

blocks|key|844785|text|$x+=+1.24

$result+=+$x+-+floor($x);

echo+$result;+//+.24|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|844786|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$x = 1.24

$result = $x - floor($x);

echo $result; // .24
</code></pre>

blocks|key|844873|text|如果你可以指望它总是有两个小数位，你可以只使用一个字符串操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844874|$decimal+=+1.25;
substr($decimal,-2);++//+returns+"25"+as+a+string|code-block|syntax|javascript|844875|不知道性能，但对于我的简单情况来说，这要好得多……|844876|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you can count on it always having 2 decimal places, you can just use a string operation: 

<pre><code>$decimal = 1.25;
substr($decimal,-2); // returns "25" as a string
</code></pre>

No idea of performance but for my simple case this was much better...

blocks|key|629054|text|为了避免额外的浮点小数(例如，50.85+-+50给0.850000000852)，在我的例子中，我只需要两个小数来表示钱分。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|629055|$n+=+50.85;
$whole+=+intval($n);
$fraction+=+$n+*+100+%25+100;|code-block|syntax|javascript|629056|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To prevent the extra float decimal (i.e. 50.85 - 50 give 0.850000000852), in my case I just need 2 decimals for money cents.

<pre><code>$n = 50.85;
$whole = intval($n);
$fraction = $n * 100 % 100;
</code></pre>

blocks|key|844771|text|我很难找到一种方法来区分美元金额和小数点后的金额。我想我大概已经弄明白了，如果你们中的任何人遇到麻烦，我想和大家分享一下|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844772|所以基本上..。|844773|如果价格是1234.44...整数将是1234，小数将是44或|844774|如果价格是1234.01...整数将是1234，小数将是01或|844775|如果价格是1234.10...整数是1234，小数是10|844776|以此类推|844777|$price+=+1234.44;

$whole+=+intval($price);+//+1234
$decimal1+=+$price+-+$whole;+//+0.44000000000005+uh+oh!+that's+why+it+needs...+(see+next+line)
$decimal2+=+round($decimal1,+2);+//+0.44+this+will+round+off+the+excess+numbers
$decimal+=+substr($decimal2,+2);+//+44+this+removed+the+first+2+characters

if+($decimal+==+1)+{+$decimal+=+10;+}+//+Michel's+warning+is+correct...
if+($decimal+==+2)+{+$decimal+=+20;+}+//+if+the+price+is+1234.10...+the+decimal+will+be+1...
if+($decimal+==+3)+{+$decimal+=+30;+}+//+so+make+sure+to+add+these+rules+too
if+($decimal+==+4)+{+$decimal+=+40;+}
if+($decimal+==+5)+{+$decimal+=+50;+}
if+($decimal+==+6)+{+$decimal+=+60;+}
if+($decimal+==+7)+{+$decimal+=+70;+}
if+($decimal+==+8)+{+$decimal+=+80;+}
if+($decimal+==+9)+{+$decimal+=+90;+}

echo+'The+dollar+amount+is+'+.+$whole+.+'+and+the+decimal+amount+is+'+.+$decimal;|code-block|syntax|javascript|844778|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|V|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|X|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|Y|8|@]|9|@]|A|$O|P]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I was having a hard time finding a way to actually separate the dollar amount and the amount after the decimal. I think I figured it out mostly and thought to share if any of yall were having trouble

So basically...

if price is 1234.44... whole would be 1234 and decimal would be 44 or

if price is 1234.01... whole would be 1234 and decimal would be 01 or

if price is 1234.10... whole would be 1234 and decimal would be 10 

and so forth

<pre><code>$price = 1234.44;

$whole = intval($price); // 1234
$decimal1 = $price - $whole; // 0.44000000000005 uh oh! that's why it needs... (see next line)
$decimal2 = round($decimal1, 2); // 0.44 this will round off the excess numbers
$decimal = substr($decimal2, 2); // 44 this removed the first 2 characters

if ($decimal == 1) { $decimal = 10; } // Michel's warning is correct...
if ($decimal == 2) { $decimal = 20; } // if the price is 1234.10... the decimal will be 1...
if ($decimal == 3) { $decimal = 30; } // so make sure to add these rules too
if ($decimal == 4) { $decimal = 40; }
if ($decimal == 5) { $decimal = 50; }
if ($decimal == 6) { $decimal = 60; }
if ($decimal == 7) { $decimal = 70; }
if ($decimal == 8) { $decimal = 80; }
if ($decimal == 9) { $decimal = 90; }

echo 'The dollar amount is ' . $whole . ' and the decimal amount is ' . $decimal;
</code></pre>

blocks|key|844891|text|试着这样..。像这样更简单|type|unstyled|depth|inlineStyleRanges|entityRanges|data|844892|$var+=+"0.98";

$decimal+=+strrchr($var,".");

$whole_no+=+$var-$decimal;

echo+$whole_no;

echo+str_replace(".",+"",+$decimal);|code-block|syntax|javascript|844893|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try it this way... it's easier like this
<pre><code>$var = &quot;0.98&quot;;

$decimal = strrchr($var,&quot;.&quot;);

$whole_no = $var-$decimal;

echo $whole_no;

echo str_replace(&quot;.&quot;, &quot;&quot;, $decimal);
</code></pre>

blocks|key|629309|text|你也可以使用类似这样的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|629310|preg_match("/([0-9]%2B)\.([0-9]%2B)/",+$number,+$matches);|code-block|syntax|javascript|629311|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could also use something like this:
<pre><code>preg_match(&quot;/([0-9]+)\.([0-9]+)/&quot;, $number, $matches);
</code></pre>

blocks|key|844987|text|如果您希望显式类型转换这两部分，那么sscanf()是一个很好的调用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|844988|代码：(Demo)|844989|var_dump(sscanf(1.25,+'%25d%25f'));|code-block|syntax|javascript|844990|输出：|844991|array(2)+{
++[0]=>
++int(1)
++[1]=>
++float(0.25)
}|844992|844993|或者，您可以分别指定这两个变量：|844994|sscanf(1.25,+'%25d%25f',+$int,+$float);
var_dump($int);
var_dump($float);|844995|844996|将小数部分转换为浮点数特别有用，例如，将小时的十进制表达式转换为小时和分钟。(Demo)|844997|$decimalTimes+=+[
++++6,
++++7.2,
++++8.78,
];

foreach+($decimalTimes+as+$decimalTime)+{
++++sscanf($decimalTime,+'%25d%25f',+$hours,+$minutes);
++++printf('%25dh%2502dm',+$hours,+round($minutes+*+60));
++++echo+"\n";
}|844998|844999|6h00m
7h12m
8h47m++//+if+round()+was+not+used,+this+would+be+8h46m|845000|entityMap|0|LINK|mutability|MUTABLE|url|https://3v4l.org/O8LQG|1|https://3v4l.org/VLbfZ^0|I|8|0|4|4|0|0|0|0|0|0|0|0|0|13|4|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1G|8|@]|D|@$9|1H|A|1I|1|1J]]|E|$]]|$1|H|3|I|5|J|7|1K|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1L|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1M|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]|$1|R|3|S|5|6|7|1O|8|@]|D|@]|E|$]]|$1|T|3|U|5|J|7|1P|8|@]|D|@]|E|$K|L]]|$1|V|3|-4|5|6|7|1Q|8|@]|D|@]|E|$]]|$1|W|3|X|5|6|7|1R|8|@]|D|@$9|1S|A|1T|1|1U]]|E|$]]|$1|Y|3|Z|5|J|7|1V|8|@]|D|@]|E|$K|L]]|$1|10|3|N|5|6|7|1W|8|@]|D|@]|E|$]]|$1|11|3|12|5|J|7|1X|8|@]|D|@]|E|$K|L]]|$1|13|3|-4|5|6|7|1Y|8|@]|D|@]|E|$]]]|14|$15|$5|16|17|18|E|$19|1A]]|1B|$5|16|17|18|E|$19|1C]]]]

If you want the two halves to be explicitly type cast, then <code>sscanf()</code> is a great call.
Code: (<a href="https://3v4l.org/O8LQG" rel="nofollow noreferrer">Demo</a>)
<pre><code>var_dump(sscanf(1.25, '%d%f'));
</code></pre>
Output:
<pre><code>array(2) {
 [0]=&gt;
 int(1)
 [1]=&gt;
 float(0.25)
}
</code></pre>
<hr />
Or you can assign the two variables individually:
<pre><code>sscanf(1.25, '%d%f', $int, $float);
var_dump($int);
var_dump($float);
</code></pre>
<hr />
Casting the decimal portion as a float is particularly useful when, say, converting decimal expression of hours to hours and minutes. (<a href="https://3v4l.org/VLbfZ" rel="nofollow noreferrer">Demo</a>)
<pre><code>$decimalTimes = [
 6,
 7.2,
 8.78,
];

foreach ($decimalTimes as $decimalTime) {
 sscanf($decimalTime, '%d%f', $hours, $minutes);
 printf('%dh%02dm', $hours, round($minutes * 60));
 echo &quot;\n&quot;;
}
</code></pre>
Output:
<pre><code>6h00m
7h12m
8h47m // if round() was not used, this would be 8h46m
</code></pre>

blocks|key|629210|text|这里没有看到一个简单的模数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|629211|$number+++++++++=+1.25;
$wholeAsFloat+++=+floor($number);+++//+1.00
$wholeAsInt+++++=+intval($number);++//+1
$decimal++++++++=+$number+%25+1;++++++//+0.25|code-block|syntax|javascript|629212|在这种情况下，同时获取$wholeAs?和$decimal并不依赖于另一个。(您可以单独获取3个输出中的1个。)我已经展示了$wholeAsFloat和$wholeAsInt，因为floor()返回一个浮点类型的数字，即使它返回的数字总是整数。(如果要将结果传递到类型提示函数参数中，这一点很重要。)|offset|length|style|CODE|629213|我希望这样可以将小时/分钟的浮点数(例如96.25+)拆分成小时和分钟，对于DateInterval实例来说是96小时15分钟。我是这样做的：|629214|$interval+=+new+\DateInterval(sprintf("PT%25dH%25dM",+intval($hours),+(($hours+%25+1)+*+60)));|629215|在我的情况下，我并不关心秒。|629216|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.floor.php|1|http://php.net/manual/en/class.dateinterval.php^0|0|0|B|9|L|8|1Q|D|24|B|2I|7|2I|7|0|0|12|C|1|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@$I|15|J|16|K|L]|$I|17|J|18|K|L]|$I|19|J|1A|K|L]|$I|1B|J|1C|K|L]|$I|1D|J|1E|K|L]]|9|@$I|1F|J|1G|1|1H]]|A|$]]|$1|M|3|N|5|6|7|1I|8|@]|9|@$I|1J|J|1K|1|1L]]|A|$]]|$1|O|3|P|5|D|7|1M|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|1N|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1O|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]|10|$5|V|W|X|A|$Y|11]]]]

Not seen a simple modulus here...

<pre><code>$number = 1.25;
$wholeAsFloat = floor($number); // 1.00
$wholeAsInt = intval($number); // 1
$decimal = $number % 1; // 0.25
</code></pre>

In this case getting both <code>$wholeAs?</code> and <code>$decimal</code> don't depend on the other. (You can just take 1 of the 3 outputs independently.) I've shown <code>$wholeAsFloat</code> and <code>$wholeAsInt</code> because <a href="http://php.net/manual/en/function.floor.php" rel="nofollow noreferrer"><code>floor()</code></a> returns a float type number even though the number it returns will always be whole. (This is important if you're passing the result into a type-hinted function parameter.)

I wanted this to split a floating point number of hours/minutes, e.g. 96.25, into hours and minutes separately for a <a href="http://php.net/manual/en/class.dateinterval.php" rel="nofollow noreferrer">DateInterval</a> instance as 96 hours 15 minutes. I did this as follows:

<pre><code>$interval = new \DateInterval(sprintf("PT%dH%dM", intval($hours), (($hours % 1) * 60)));
</code></pre>

I didn't care about seconds in my case.

blocks|key|844608|text|val+=+-3.1234

fraction+=+abs(val+-+as.integer(val)+)+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|844609|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>val = -3.1234

fraction = abs(val - as.integer(val) ) 
</code></pre>

Given, say, 1.25 - how do I get "1" and ."25" parts of this number? 

I need to check if the decimal part is .0, .25, .5, or .75.

How to get whole and decimal part of a number?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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假设是1.25，我该如何得到这个数字的"1“和”25“部分呢？我需要检查小数部分是.0、.25、.5还是.75。

问如何得到一个数字的整数和小数部分？
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问如何得到一个数字的整数和小数部分？
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