问在使用mysql和ajax时访问json字符串中的变量时出现问题

EN

$(function() {
  var jqxhr = $.ajax({
    type: "POST",
    url: "test.php",
    async: false,
    cache: false,
    timeout: 10000,
    data: {
      test: "test"
    },
    success: function(response) {
      console.log(response); // {"login":"1","status_":0,"user":1}
      console.log(response.login); //undefined
      test = JSON.parse(response); // Uncaught SyntaxError: Unexpected token  in JSON at position 2
      console.log(test.login); //not work 
    },
    complete: function(response) {
    }
  });
})();

test.php
require("config.php");
require("dbconnect.php");
$sth = $dbh->prepare('SELECT * FROM users WHERE email=?');
$sth->bindParam(1, $_POST["login"], PDO::PARAM_STR);
$sth->execute();
$user = $sth->fetch();
if(@$user['email']==$_POST["test"]) { 
$json = json_encode(array("login" =>"1","status_"=>0, "user" => 1), JSON_UNESCAPED_UNICODE);
}
else { 
$json = json_encode(array("login" =>"1", "status_"=>1, "user" => 1), JSON_UNESCAPED_UNICODE);
}
echo $json;

require("config.php");
require("dbconnect.php");
$sth = $dbh->prepare('SELECT * FROM users WHERE email=?');
$sth->bindParam(1, $_POST["test"], PDO::PARAM_STR);
$sth->execute();
$user = $sth->fetch();