从多个链接列表中获取具有特定模式的链接列表

import re

def get_links_with_pattern(link_lists, pattern):
    matched_links = []
    for link_list in link_lists:
        for link in link_list:
            if re.match(pattern, link):
                matched_links.append(link)
    return matched_links

# 示例链接列表
link_lists = [
    ['https://example.com', 'https://example.org', 'https://example.net'],
    ['https://example.com/foo', 'https://example.org/bar', 'https://example.net/baz'],
    ['https://example.com/123', 'https://example.org/456', 'https://example.net/789']
]

# 示例链接模式
pattern = r'https://example\.com/.*'

# 获取具有特定模式的链接列表
matched_links = get_links_with_pattern(link_lists, pattern)

# 打印结果
for link in matched_links:
    print(link)