从路径和值创建嵌套字典

def create_nested_dict(paths, values):
    if len(paths) != len(values):
        raise ValueError("Paths and values must have the same length")
    
    nested_dict = {}
    for path, value in zip(paths, values):
        current_level = nested_dict
        for key in path[:-1]:
            if key not in current_level:
                current_level[key] = {}
            current_level = current_level[key]
        current_level[path[-1]] = value
    
    return nested_dict

# 示例路径和值
paths = [["a", "b", "c"], ["a", "d"], ["e"]]
values = [1, 2, 3]

# 创建嵌套字典
nested_dict = create_nested_dict(paths, values)
print(nested_dict)

{
    'a': {
        'b': {
            'c': 1
        },
        'd': 2
    },
    'e': 3
}