从PHP传递Python的有效路径

$python_script = "/path/to/python_script.py";
$arg1 = "arg1_value";
$arg2 = "arg2_value";

exec("python3 " . $python_script . " " . escapeshellarg($arg1) . " " . escapeshellarg($arg2), $output, $return_var);

if ($return_var === 0) {
    // 执行成功
    echo "Output: " . implode("\n", $output);
} else {
    // 执行失败
    echo "Error: " . implode("\n", $output);
}

import sys

arg1 = sys.argv[1]
arg2 = sys.argv[2]

# 在这里编写Python代码，使用arg1和arg2作为参数