从iOS发送多部分POST并在PHP $ _POST中读取参数？

import Foundation

let url = URL(string: "https://example.com/upload.php")!
var request = URLRequest(url: url)
request.httpMethod = "POST"

let boundary = "Boundary-\(UUID().uuidString)"
request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")

let data = "your data".data(using: .utf8)!

var body = Data()
body.append("--\(boundary)\r\n".data(using: .utf8)!)
body.append("Content-Disposition: form-data; name=\"file\"; filename=\"file.jpg\"\r\n".data(using: .utf8)!)
body.append("Content-Type: image/jpeg\r\n\r\n".data(using: .utf8)!)
body.append(data)
body.append("\r\n".data(using: .utf8)!)
body.append("--\(boundary)--\r\n".data(using: .utf8)!)

request.httpBody = body

let task = URLSession.shared.dataTask(with: request) { data, response, error in
    guard let data = data, error == nil else {
        print("error=\(error!)")
        return
    }
    if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {
        print("statusCode should be 200, but is \(httpStatus.statusCode)")
        print("response = \(response!)")
        return
    }
    let responseString = String(data: data, encoding: .utf8)
    print("responseString = \(responseString!)")
}
task.resume()

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $file = $_FILES['file']['name'];
    $file_tmp = $_FILES['file']['tmp_name'];
    move_uploaded_file($file_tmp, "uploads/$file");
    echo "File uploaded successfully.";
} else {
    echo "Invalid request method.";
}
?>