你如何统计玩家在一系列tictactoe(x和o)回放中的胜负和平局？

def check_game_over(board):
    # 检查每一行
    for row in board:
        if row[0] == row[1] == row[2] != '':
            return True
    # 检查每一列
    for col in range(3):
        if board[0][col] == board[1][col] == board[2][col] != '':
            return True
    # 检查对角线
    if board[0][0] == board[1][1] == board[2][2] != '':
        return True
    if board[0][2] == board[1][1] == board[2][0] != '':
        return True
    # 检查是否平局
    if all(board[i][j] != '' for i in range(3) for j in range(3)):
        return True
    return False

def count_results(replays):
    player1_wins = 0
    player2_wins = 0
    draws = 0

    for replay in replays:
        board = [[''] * 3 for _ in range(3)]
        for move in replay:
            row, col, player = move
            board[row][col] = player

        if check_game_over(board):
            if player == 'x':
                player1_wins += 1
            else:
                player2_wins += 1
        else:
            draws += 1

    return player1_wins, player2_wins, draws

# 示例回放数据
replays = [
    [(0, 0, 'x'), (0, 1, 'o'), (1, 1, 'x'), (1, 0, 'o'), (2, 2, 'x')],
    [(0, 0, 'x'), (0, 1, 'o'), (1, 1, 'x'), (1, 0, 'o'), (2, 0, 'x'), (2, 2, 'o')],
    [(0, 0, 'x'), (0, 1, 'o'), (1, 1, 'x'), (1, 0, 'o'), (2, 0, 'x'), (2, 1, 'o'), (0, 2, 'x')],
    [(0, 0, 'x'), (0, 1, 'o'), (1, 1, 'x'), (1, 0, 'o'), (2, 0, 'x'), (2, 1, 'o'), (2, 2, 'x')],
]

player1_wins, player2_wins, draws = count_results(replays)

print("Player 1 wins:", player1_wins)
print("Player 2 wins:", player2_wins)
print("Draws:", draws)