使用嵌套键值的总和对嵌套字典进行排序

def sort_nested_dict(nested_dict):
    # 计算嵌套键值的总和并添加到字典中
    for key, value in nested_dict.items():
        if isinstance(value, dict):
            nested_dict[key]['sum'] = sum(value.values())
    
    # 对字典进行排序
    sorted_dict = dict(sorted(nested_dict.items(), key=lambda x: x[1]['sum']))
    
    # 重新构建有序的嵌套字典
    sorted_nested_dict = {}
    for key, value in sorted_dict.items():
        sorted_nested_dict[key] = value
        sorted_nested_dict[key].pop('sum')
    
    return sorted_nested_dict

# 示例嵌套字典
nested_dict = {
    'dict1': {'key1': 10, 'key2': 20},
    'dict2': {'key1': 5, 'key2': 15},
    'dict3': {'key1': 8, 'key2': 12}
}

# 对嵌套字典进行排序
sorted_nested_dict = sort_nested_dict(nested_dict)

# 输出排序结果
for key, value in sorted_nested_dict.items():
    print(key, value)

dict2 {'key1': 5, 'key2': 15}
dict3 {'key1': 8, 'key2': 12}
dict1 {'key1': 10, 'key2': 20}