使用Jackson将Java对象转换为JSON

import com.fasterxml.jackson.databind.ObjectMapper;

public class JacksonExample {
    public static void main(String[] args) {
        // 创建一个Java对象
        Person person = new Person("John", 30);

        try {
            // 创建ObjectMapper对象
            ObjectMapper objectMapper = new ObjectMapper();

            // 将Java对象转换为JSON字符串
            String jsonString = objectMapper.writeValueAsString(person);

            // 输出JSON字符串
            System.out.println(jsonString);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    // Getters and setters (required for Jackson to work)
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

// 确保Person类有getter和setter方法
public class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

import com.fasterxml.jackson.annotation.JsonIgnoreProperties;

@JsonIgnoreProperties(ignoreUnknown = true)
public class Person {
    // ...
}