列表字典的笛卡尔积

import itertools

list1 = [1, 2, 3]
list2 = ['a', 'b', 'c']

# 计算列表的笛卡尔积
product = itertools.product(list1, list2)

# 将结果转换为列表并输出
result = list(product)
print(result)

[(1, 'a'), (1, 'b'), (1, 'c'), (2, 'a'), (2, 'b'), (2, 'c'), (3, 'a'), (3, 'b'), (3, 'c')]

import itertools

dict1 = {'a': [1, 2], 'b': [3, 4]}
dict2 = {'c': [5, 6], 'd': [7, 8]}

# 计算字典的笛卡尔积
product = itertools.product(*dict1.values(), *dict2.values())

# 将结果转换为字典并输出
result = [dict(zip(dict1.keys(), x), **dict(zip(dict2.keys(), y))) for x, y in product]
print(result)

[{'a': 1, 'b': 3, 'c': 5, 'd': 7}, {'a': 1, 'b': 3, 'c': 5, 'd': 8}, {'a': 1, 'b': 3, 'c': 6, 'd': 7}, {'a': 1, 'b': 3, 'c': 6, 'd': 8}, {'a': 1, 'b': 4, 'c': 5, 'd': 7}, {'a': 1, 'b': 4, 'c': 5, 'd': 8}, {'a': 1, 'b': 4, 'c': 6, 'd': 7}, {'a': 1, 'b': 4, 'c': 6, 'd': 8}, {'a': 2, 'b': 3, 'c': 5, 'd': 7}, {'a': 2, 'b': 3, 'c': 5, 'd': 8}, {'a': 2, 'b': 3, 'c': 6, 'd': 7}, {'a': 2, 'b': 3, 'c': 6, 'd': 8}, {'a': 2, 'b': 4, 'c': 5, 'd': 7}, {'a': 2, 'b': 4, 'c': 5, 'd': 8}, {'a': 2, 'b': 4, 'c': 6, 'd': 7}, {'a': 2, 'b': 4, 'c': 6, 'd': 8}]