删除部分字符串/ url查询参数的Javascript

function removeQueryParam(url, param) {
  const searchParams = new URLSearchParams(url.search);
  searchParams.delete(param);
  return url.origin + url.pathname + '?' + searchParams.toString() + url.hash;
}

// 示例用法
const url = new URL('https://www.example.com/?param1=value1&param2=value2');
const updatedUrl = removeQueryParam(url, 'param1');
console.log(updatedUrl);

function removeQueryParam(url, param) {
  const regex = new RegExp(`([?&])${param}=[^&]*[&]?`, 'i');
  return url.replace(regex, '$1').replace(/[?&]$/, '');
}

// 示例用法
const url = 'https://www.example.com/?param1=value1&param2=value2';
const updatedUrl = removeQueryParam(url, 'param1');
console.log(updatedUrl);

function removeQueryParam(url, param) {
  const urlObj = new URL(url);
  urlObj.searchParams.delete(param);
  return urlObj.href;
}

// 示例用法
const url = 'https://www.example.com/?param1=value1&param2=value2';
const updatedUrl = removeQueryParam(url, 'param1');
console.log(updatedUrl);