在不触发异常的情况下检查Java中是否存在Getters

import java.lang.reflect.Method;

public class GetterChecker {

    public static boolean hasGetter(Class<?> clazz, String propertyName) {
        if (propertyName == null || propertyName.isEmpty()) {
            return false;
        }

        String capitalized = capitalize(propertyName);
        String getterName = "get" + capitalized;

        try {
            Method method = clazz.getMethod(getterName);
            return method != null && !method.isBridge() && !method.isSynthetic();
        } catch (NoSuchMethodException e) {
            return false;
        }
    }

    private static String capitalize(String str) {
        if (str == null || str.isEmpty()) {
            return str;
        }
        return str.substring(0, 1).toUpperCase() + str.substring(1);
    }

    public static void main(String[] args) {
        // 示例类
        class Example {
            private String name;

            public String getName() {
                return name;
            }
        }

        boolean hasNameGetter = hasGetter(Example.class, "name");
        System.out.println("Has 'getName' getter: " + hasNameGetter); // 应该输出 true
    }
}