在没有sprintf的情况下将整数转换为C中的字符串

#include<stdio.h>
#include <stdlib.h>

char* itoa(int num, char* str, int base) {
    int i = 0;
    int isNegative = 0;

    if (num == 0) {
        str[i++] = '0';
        str[i] = '\0';
        return str;
    }

    if (num < 0 && base == 10) {
        isNegative = 1;
        num = -num;
    }

    while (num != 0) {
        int rem = num % base;
        str[i++] = (rem > 9) ? (rem - 10) + 'a' : rem + '0';
        num = num / base;
    }

    if (isNegative) {
        str[i++] = '-';
    }

    str[i] = '\0';

    reverse(str);

    return str;
}

int main() {
    int num = -1234;
    char str[100];
    itoa(num, str, 10);
    printf("String representation of %d: %s\n", num, str);
    return 0;
}

String representation of -1234: -1234