在选项卡栏上显示弹出窗口按钮单击react native

import React, { useState } from 'react';
import { View, Text, TouchableOpacity, Modal } from 'react-native';

const App = () => {
  const [modalVisible, setModalVisible] = useState(false);

  const handleButtonClick = () => {
    setModalVisible(true);
  };

  const handleModalClose = () => {
    setModalVisible(false);
  };

  return (
    <View>
      <TabBar>
        {/* 其他选项卡内容 */}
        <TabBarItem>
          <TouchableOpacity onPress={handleButtonClick}>
            <Text>弹出窗口按钮</Text>
          </TouchableOpacity>
        </TabBarItem>
        {/* 其他选项卡内容 */}
      </TabBar>

      <Modal visible={modalVisible} onRequestClose={handleModalClose}>
        {/* 弹出窗口内容 */}
      </Modal>
    </View>
  );
};

export default App;