在Android中传递right GET调用中的参数的正确方式是什么？

import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;

public class MainActivity extends AppCompatActivity {
    // ...

    private void makeGetRequest(String username, String password) {
        try {
            // 构建URL
            String baseUrl = "https://example.com/api/users";

            // 构建参数并进行URL编码
            String encodedUsername = URLEncoder.encode(username, "UTF-8");
            String encodedPassword = URLEncoder.encode(password, "UTF-8");

            // 构建查询字符串
            String queryString = "?username=" + encodedUsername + "&password=" + encodedPassword;

            // 构建完整的URL
            String url = baseUrl + queryString;

            // 发起GET请求
            RequestQueue queue = Volley.newRequestQueue(this);
            StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
                    new Response.Listener<String>() {
                        @Override
                        public void onResponse(String response) {
                            // 处理响应
                        }
                    }, new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    // 处理错误
                }
            });

            queue.add(stringRequest);
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        }
    }

    // ...
}