在C++编程中,使用#define
的替代方法是为了避免一些#define
的局限性,如预处理指令无法被const
限定、#define
定义的宏名称在代码中可见等。以下是一些常用的替代方法:
const
限定符:
#include <iostream>
int main() {
const int value = 42;
std::cout << "Value: " << value << std::endl;
return 0;
}
inline
关键字:
#include <iostream>
inline int add(int a, int b) {
return a + b;
}
int main() {
int x = 10;
int y = 20;
int sum = add(x, y);
std::cout << "Sum: " << sum << std::endl;
return 0;
}
constexpr
关键字:
#include <iostream>
constexpr int add(int a, int b) {
return a + b;
}
int main() {
int x = 10;
int y = 20;
int sum = add(x, y);
std::cout << "Sum: " << sum << std::endl;
return 0;
}
inline
和constexpr
关键字:
#include <iostream>
inline constexpr int add(int a, int b) {
return a + b;
}
int main() {
int x = 10;
int y = 20;
int sum = add(x, y);
std::cout << "Sum: " << sum << std::endl;
return 0;
}
#define
定义常量:
#include <iostream>
#define CONSTANT_VALUE 42
int main() {
int value = CONSTANT_VALUE;
std::cout << "Value: " << value << std::endl;
return 0;
}
constexpr
定义常量:
#include <iostream>
constexpr int value = 42;
int main() {
std::cout << "Value: " << value << std::endl;
return 0;
}
constexpr
关键字:
#include <iostream>
constexpr int add(int a, int b) {
return a + b;
}
int main() {
int x = 10;
int y = 20;
int sum = add(x, y);
std::cout << "Sum: " << sum << std::endl;
return 0;
}
inline
关键字:
#include <iostream>
inline int add(int a, int b) {
return a + b;
}
int main() {
int x = 10;
int y = 20;
int sum = add(x, y);
std::cout << "Sum: " << sum << std::endl;
return 0;
}
constexpr
关键字和inline
关键字:
#include <iostream>
constexpr inline int add(int a, int b) {
return a + b;
}
int main() {
int x = 10;
int y = 20;
int sum = add(x, y);
std::cout << "Sum: " << sum << std::endl;
return 0;
}
inline
关键字和constexpr
关键字:```c++
#include <iostream>
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