在Django中分别呈现状态为Accept或Reject的特定模板中的对象

from django.db import models

class Object(models.Model):
    STATUS_CHOICES = (
        ('Accept', 'Accept'),
        ('Reject', 'Reject'),
    )
    status = models.CharField(max_length=10, choices=STATUS_CHOICES)
    # 其他字段...

    def __str__(self):
        return self.status

from django.shortcuts import render
from .models import Object

def specific_template(request):
    accept_objects = Object.objects.filter(status='Accept')
    reject_objects = Object.objects.filter(status='Reject')
    context = {
        'accept_objects': accept_objects,
        'reject_objects': reject_objects,
    }
    return render(request, 'specific_template.html', context)

<!-- specific_template.html -->
<h1>Accept Objects:</h1>
<ul>
  {% for object in accept_objects %}
    <li>{{ object }}</li>
  {% empty %}
    <li>No accept objects found.</li>
  {% endfor %}
</ul>

<h1>Reject Objects:</h1>
<ul>
  {% for object in reject_objects %}
    <li>{{ object }}</li>
  {% empty %}
    <li>No reject objects found.</li>
  {% endfor %}
</ul>