在c++中使用dword检查多个布尔条件

#include <iostream>

int main() {
    bool condition1 = true;
    bool condition2 = false;
    bool condition3 = true;

    DWORD conditions = 0;

    // 将每个布尔条件的状态映射到DWORD的每一位上
    conditions |= (condition1 ? 1 : 0) << 0;
    conditions |= (condition2 ? 1 : 0) << 1;
    conditions |= (condition3 ? 1 : 0) << 2;

    // 检查DWORD中每一位的状态
    bool isCondition1True = (conditions & (1 << 0)) != 0;
    bool isCondition2True = (conditions & (1 << 1)) != 0;
    bool isCondition3True = (conditions & (1 << 2)) != 0;

    std::cout << "Condition 1 is " << (isCondition1True ? "true" : "false") << std::endl;
    std::cout << "Condition 2 is " << (isCondition2True ? "true" : "false") << std::endl;
    std::cout << "Condition 3 is " << (isCondition3True ? "true" : "false") << std::endl;

    return 0;
}