在python中有没有一种创建单链表的可变方法？

class ListNode:
    def __init__(self, val=0, next=None):
        self.val = val
        self.next = next

def createLinkedList(nums):
    head = ListNode()
    curr = head
    for num in nums:
        curr.next = ListNode(num)
        curr = curr.next
    return head.next

nums = [1, 2, 3, 4, 5]
head = createLinkedList(nums)

# 遍历链表并打印节点的值
curr = head
while curr:
    print(curr.val)
    curr = curr.next

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