在xml中获取所有同级减去self的建议方法

./following-sibling::*

from lxml import etree

xml = """
<root>
  <node1>...</node1>
  <node2>...</node2>
  <node3>...</node3>
</root>
"""

# 解析XML
root = etree.fromstring(xml)

# 执行XPath查询
nodes = root.xpath("./following-sibling::*")

# 遍历结果
for node in nodes:
    print(etree.tostring(node, encoding="unicode"))

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.*;

import org.w3c.dom.Document;
import org.w3c.dom.NodeList;

String xml = "<root>...</root>";

// 解析XML
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new InputSource(new StringReader(xml)));

// 创建XPath对象
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();

// 执行XPath查询
XPathExpression expr = xpath.compile("./following-sibling::*");
NodeList nodes = (NodeList) expr.evaluate(document, XPathConstants.NODESET);

// 遍历结果
for (int i = 0; i < nodes.getLength(); i++) {
    System.out.println(nodes.item(i).getNodeName());
}