在xslt中按连续日期分组，按相似日期求和

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="/">
    <xsl:for-each-group select="dates/date" group-starting-with="date[xs:date(.) - xs:date(preceding-sibling::date[1]) ne xs:dayTimeDuration('P1D')]">
      <group>
        <xsl:attribute name="start-date" select="current-group()[1]"/>
        <xsl:attribute name="end-date" select="current-group()[last()]"/>
        <sum>
          <xsl:value-of select="sum(current-group())"/>
        </sum>
      </group>
    </xsl:for-each-group>
  </xsl:template>

</xsl:stylesheet>