如何从数组中删除空元素，但也要使用布尔值

const array = [0, 1, false, 2, '', 3, null, 4, undefined, 5];
const filteredArray = array.filter(Boolean);

console.log(filteredArray); // 输出: [1, 2, 3, 4, 5]

array = [0, 1, False, 2, '', 3, None, 4, [], 5]
filtered_array = [x for x in array if x]

print(filtered_array)  # 输出: [1, 2, 3, 4, 5]

import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

public class Main {
    public static void main(String[] args) {
        List<Object> list = Arrays.asList(0, 1, false, 2, "", 3, null, 4, new Object(), 5);
        List<Object> filteredList = list.stream()
                                       .filter(e -> e != null && !e.toString().isEmpty())
                                       .collect(Collectors.toList());

        System.out.println(filteredList); // 输出: [1, 2, 3, 4, 5]
    }
}

const array = [0, 1, false, 2, '', 3, null, 4, undefined, 5];
const filteredArray = array.filter(item => item !== null && item !== undefined);

console.log(filteredArray); // 输出: [0, 1, false, 2, '', 3, 4, 5]