如何从文本字符串中将时间拆分为天、小时、分钟、秒

import re

def split_time_from_string(time_string):
    # 正则表达式匹配时间格式
    pattern = r'(\d+)-(\d+)-(\d+) (\d+):(\d+):(\d+)'
    match = re.match(pattern, time_string)
    
    if match:
        # 提取匹配到的时间部分
        year = int(match.group(1))
        month = int(match.group(2))
        day = int(match.group(3))
        hour = int(match.group(4))
        minute = int(match.group(5))
        second = int(match.group(6))
        
        # 计算时间差
        current_time = datetime.datetime.now()
        target_time = datetime.datetime(year, month, day, hour, minute, second)
        time_diff = current_time - target_time
        
        # 将时间差转换为天、小时、分钟、秒
        days = time_diff.days
        hours = time_diff.seconds // 3600
        minutes = (time_diff.seconds % 3600) // 60
        seconds = time_diff.seconds % 60
        
        return days, hours, minutes, seconds
    else:
        return None

# 示例用法
time_string = "2022-01-01 12:30:00"
result = split_time_from_string(time_string)
if result:
    days, hours, minutes, seconds = result
    print(f"时间差为：{days}天 {hours}小时 {minutes}分钟 {seconds}秒")
else:
    print("时间格式不正确")