如何从长度未知的文本框中获取每两个字符的子字符串

def get_substrings(text):
    substrings = []
    for i in range(0, len(text), 2):
        substrings.append(text[i:i+2])
    return substrings

# 示例
text = "abcdef"
result = get_substrings(text)
print(result)  # 输出: ['ab', 'cd', 'ef']

function getSubstrings(text) {
    let substrings = [];
    for (let i = 0; i < text.length; i += 2) {
        substrings.push(text.substring(i, i + 2));
    }
    return substrings;
}

// 示例
let text = "abcdef";
let result = getSubstrings(text);
console.log(result);  // 输出: ['ab', 'cd', 'ef']

import java.util.ArrayList;
import java.util.List;

public class SubstringExample {
    public static List<String> getSubstrings(String text) {
        List<String> substrings = new ArrayList<>();
        for (int i = 0; i < text.length(); i += 2) {
            if (i + 1 < text.length()) {
                substrings.add(text.substring(i, i + 2));
            } else {
                substrings.add(text.substring(i, i + 1));
            }
        }
        return substrings;
    }

    public static void main(String[] args) {
        String text = "abcdef";
        List<String> result = getSubstrings(text);
        System.out.println(result);  // 输出: [ab, cd, ef]
    }
}

using System;
using System.Collections.Generic;

class Program
{
    static List<string> GetSubstrings(string text)
    {
        List<string> substrings = new List<string>();
        for (int i = 0; i < text.Length; i += 2)
        {
            if (i + 1 < text.Length)
            {
                substrings.Add(text.Substring(i, 2));
            }
            else
            {
                substrings.Add(text.Substring(i, 1));
            }
        }
        return substrings;
    }

    static void Main()
    {
        string text = "abcdef";
        List<string> result = GetSubstrings(text);
        Console.WriteLine(string.Join(", ", result));  // 输出: ab, cd, ef
    }
}