如何从java或Android中的字符串生成XML文档？

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.OutputKeys;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;

import org.w3c.dom.Document;
import org.w3c.dom.Element;

public class StringToXML {
    public static void main(String[] args) {
        try {
            String xmlString = "<root><name>John Doe</name><age>30</age></root>";
            DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
            DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
            InputSource is = new InputSource(new StringReader(xmlString));
            Document doc = dBuilder.parse(is);

            // 将生成的XML文档输出到控制台
            TransformerFactory transformerFactory = TransformerFactory.newInstance();
            Transformer transformer = transformerFactory.newTransformer();
            transformer.setOutputProperty(OutputKeys.INDENT, "yes");
            DOMSource source = new DOMSource(doc);
            StreamResult console = new StreamResult(System.out);
            transformer.transform(source, console);

        } catch (ParserConfigurationException | SAXException | IOException | TransformerException e) {
            e.printStackTrace();
        }
    }
}

import org.apache.commons.text.StringEscapeUtils;

public class StringToXML {
    public static void main(String[] args) {
        String xmlString = "<root><name>John Doe</name><age>30</age></root>";
        String escapedXml = StringEscapeUtils.escapeXml11(xmlString);
        System.out.println(escapedXml);
    }
}