如何使用JAXB创建没有值的XmlElement

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class MyClass {
    @XmlElement(nillable = true)
    private String myElement;
    
    // 其他属性和方法
}

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import java.io.StringWriter;

public class Main {
    public static void main(String[] args) {
        MyClass myObject = new MyClass();
        myObject.setMyElement(null);
        
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(MyClass.class);
            Marshaller marshaller = jaxbContext.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
            
            StringWriter writer = new StringWriter();
            marshaller.marshal(myObject, writer);
            
            String xml = writer.toString();
            System.out.println(xml);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<myClass>
    <myElement xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
</myClass>