如何使用PHP在多个下拉式表单数据库中显示相同的记录？

<?php
// 连接数据库
$servername = "数据库服务器地址";
$username = "数据库用户名";
$password = "数据库密码";
$dbname = "数据库名";

$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {
    die("连接数据库失败: " . $conn->connect_error);
}

// 查询数据库
$sql = "SELECT * FROM 表名";
$result = $conn->query($sql);

// 创建下拉式表单
echo "<select name='dropdown1'>";
echo "<option value=''>请选择</option>";

// 循环输出选项
if ($result->num_rows > 0) {
    while ($row = $result->fetch_assoc()) {
        echo "<option value='" . $row["字段名"] . "'>" . $row["字段名"] . "</option>";
    }
}

echo "</select>";

// 创建第二个下拉式表单
echo "<select name='dropdown2'>";
echo "<option value=''>请选择</option>";

// 循环输出选项
if ($result->num_rows > 0) {
    $result->data_seek(0); // 重置查询结果指针到起始位置
    while ($row = $result->fetch_assoc()) {
        echo "<option value='" . $row["字段名"] . "'>" . $row["字段名"] . "</option>";
    }
}

echo "</select>";

// 关闭数据库连接
$conn->close();
?>