如何使用jsoup从div中的%2中选择%1跨度

<dependency>
    <groupId>org.jsoup</groupId>
    <artifactId>jsoup</artifactId>
    <version>1.14.3</version>
</dependency>

String html = "<div>%1</div><div>%2</div>";
Document doc = Jsoup.parse(html);

Elements divs = doc.select("div:contains(%2)");

Pattern pattern = Pattern.compile("%1\\s*(\\d+)");
for (Element div : divs) {
    Matcher matcher = pattern.matcher(div.text());
    if (matcher.find()) {
        String span = matcher.group(1);
        System.out.println("跨度内容：" + span);
    }
}