如何使用verhoeff算法验证输入的aadhar数是否有效？

# Verhoeff算法的乘法表和置换表
multiplication_table = [
    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
    [1, 2, 3, 4, 0, 6, 7, 8, 9, 5],
    [2, 3, 4, 0, 1, 7, 8, 9, 5, 6],
    [3, 4, 0, 1, 2, 8, 9, 5, 6, 7],
    [4, 0, 1, 2, 3, 9, 5, 6, 7, 8],
    [5, 9, 8, 7, 6, 0, 4, 3, 2, 1],
    [6, 5, 9, 8, 7, 1, 0, 4, 3, 2],
    [7, 6, 5, 9, 8, 2, 1, 0, 4, 3],
    [8, 7, 6, 5, 9, 3, 2, 1, 0, 4],
    [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
]

permutation_table = [
    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
    [1, 5, 7, 6, 2, 8, 3, 0, 9, 4],
    [5, 8, 0, 3, 7, 9, 6, 1, 4, 2],
    [8, 9, 1, 6, 0, 4, 3, 5, 2, 7],
    [9, 4, 5, 3, 1, 2, 6, 8, 7, 0],
    [4, 2, 8, 6, 5, 7, 3, 9, 0, 1],
    [2, 7, 9, 3, 8, 0, 6, 4, 1, 5],
    [7, 0, 4, 6, 9, 1, 3, 2, 5, 8]
]

# 验证Aadhar号码是否有效
def validate_aadhar(aadhar):
    # 将Aadhar号码转换为数字数组
    digits = [int(digit) for digit in str(aadhar)]

    # 计算校验位
    checksum = 0
    for i, digit in enumerate(digits[::-1]):
        row = i % 8
        column = digit
        checksum = multiplication_table[checksum][permutation_table[row][column]]

    # 验证Aadhar号码
    if checksum == 0:
        return "有效的Aadhar号码"
    else:
        return "无效的Aadhar号码"

# 示例输入
aadhar_number = 123456789012

# 验证Aadhar号码是否有效
result = validate_aadhar(aadhar_number)
print(result)