如何使用webview将post param传递给url？

WebView webView = new WebView(context);
webView.loadUrl("http://www.example.com");

webView.setWebViewClient(new WebViewClient() {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
        // 在此处处理URL加载请求
        return super.shouldOverrideUrlLoading(view, request);
    }
});

@Override
public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
    String url = request.getUrl().toString();
    if (url.equals("http://www.example.com/submit")) {
        // 构建POST参数
        String postData = "param1=value1&param2=value2";
        byte[] postDataBytes = postData.getBytes(StandardCharsets.UTF_8);

        // 发送POST请求
        view.postUrl(url, postDataBytes);

        return true; // 返回true表示已经处理了URL加载请求
    }

    return super.shouldOverrideUrlLoading(view, request);
}