如何发送GET请求而不等待响应

// 使用XMLHttpRequest对象发送异步GET请求
var xhr = new XMLHttpRequest();
xhr.open('GET', 'https://example.com/api', true);
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4 && xhr.status === 200) {
    // 请求成功，处理响应数据
    var response = JSON.parse(xhr.responseText);
    console.log(response);
  }
};
xhr.send();

// 使用Fetch API发送异步GET请求
fetch('https://example.com/api')
  .then(function(response) {
    if (response.ok) {
      return response.json();
    } else {
      throw new Error('请求失败');
    }
  })
  .then(function(data) {
    // 请求成功，处理响应数据
    console.log(data);
  })
  .catch(function(error) {
    // 请求失败，处理错误
    console.error(error);
  });

import requests

response = requests.get('https://example.com/api')
if response.status_code == 200:
    data = response.json()
    print(data)

import okhttp3.*;

OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
        .url("https://example.com/api")
        .build();
client.newCall(request).enqueue(new Callback() {
    @Override
    public void onResponse(Call call, Response response) throws IOException {
        if (response.isSuccessful()) {
            String data = response.body().string();
            System.out.println(data);
        }
    }

    @Override
    public void onFailure(Call call, IOException e) {
        e.printStackTrace();
    }
});