如何在不使用时间增量的情况下转到时间序列中的下一个日期

import datetime

def get_next_date(current_date, time_series):
    # 解析时间序列
    dates = [datetime.datetime.strptime(date_str, "%Y-%m-%d") for date_str in time_series]
    
    # 获取当前日期的索引位置
    current_index = dates.index(current_date)
    
    # 获取下一个日期
    next_index = (current_index + 1) % len(dates)
    next_date = dates[next_index]
    
    # 考虑月末和年末的情况
    if current_date.day == datetime.datetime(current_date.year, current_date.month, 1).replace(day=28).day:
        next_date = next_date.replace(day=1)
    if current_date.month == 12 and current_date.day == 31:
        next_date = next_date.replace(year=current_date.year + 1)
    
    return next_date.strftime("%Y-%m-%d")

# 示例用法
current_date = datetime.datetime.now().date()
time_series = ["2022-01-01", "2022-01-02", "2022-01-03", "2022-01-04"]
next_date = get_next_date(current_date, time_series)
print(next_date)