在没有比较器的情况下,可以通过实现Comparable接口来对对象数组进行排序。下面是使用Java中的MergeSort算法对对象数组进行排序的步骤:
public class MyObject implements Comparable<MyObject> {
private int value;
public MyObject(int value) {
this.value = value;
}
public int getValue() {
return value;
}
@Override
public int compareTo(MyObject other) {
return Integer.compare(this.value, other.value);
}
}
public class MergeSort {
public static void mergeSort(MyObject[] arr) {
if (arr == null || arr.length <= 1) {
return;
}
mergeSort(arr, 0, arr.length - 1);
}
private static void mergeSort(MyObject[] arr, int left, int right) {
if (left < right) {
int mid = (left + right) / 2;
mergeSort(arr, left, mid);
mergeSort(arr, mid + 1, right);
merge(arr, left, mid, right);
}
}
private static void merge(MyObject[] arr, int left, int mid, int right) {
int n1 = mid - left + 1;
int n2 = right - mid;
MyObject[] leftArr = new MyObject[n1];
MyObject[] rightArr = new MyObject[n2];
for (int i = 0; i < n1; i++) {
leftArr[i] = arr[left + i];
}
for (int j = 0; j < n2; j++) {
rightArr[j] = arr[mid + 1 + j];
}
int i = 0, j = 0;
int k = left;
while (i < n1 && j < n2) {
if (leftArr[i].compareTo(rightArr[j]) <= 0) {
arr[k] = leftArr[i];
i++;
} else {
arr[k] = rightArr[j];
j++;
}
k++;
}
while (i < n1) {
arr[k] = leftArr[i];
i++;
k++;
}
while (j < n2) {
arr[k] = rightArr[j];
j++;
k++;
}
}
}
public class Main {
public static void main(String[] args) {
MyObject[] arr = new MyObject[5];
arr[0] = new MyObject(5);
arr[1] = new MyObject(2);
arr[2] = new MyObject(8);
arr[3] = new MyObject(1);
arr[4] = new MyObject(3);
MergeSort.mergeSort(arr);
for (MyObject obj : arr) {
System.out.println(obj.getValue());
}
}
}
以上代码将会输出排序后的对象数组:
1
2
3
5
8
这是使用MergeSort对对象数组进行排序的基本步骤。在实际应用中,可以根据具体需求对代码进行适当的修改和优化。
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