如何在没有迭代的情况下基于int计数器设置多个bool标志？

#include<iostream>
using namespace std;

int main() {
    int counter = 0;
    bool flag1 = false;
    bool flag2 = false;
    bool flag3 = false;

    // 设置第一个标志
    counter |= 1;
    flag1 = (counter & 1) == 1;
    cout << "flag1: "<< flag1<< endl;

    // 设置第二个标志
    counter |= 2;
    flag2 = (counter & 2) == 2;
    cout << "flag2: "<< flag2<< endl;

    // 设置第三个标志
    counter |= 4;
    flag3 = (counter & 4) == 4;
    cout << "flag3: "<< flag3<< endl;

    // 清除第一个标志
    counter &= ~1;
    flag1 = (counter & 1) == 1;
    cout << "flag1: "<< flag1<< endl;

    // 清除第二个标志
    counter &= ~2;
    flag2 = (counter & 2) == 2;
    cout << "flag2: "<< flag2<< endl;

    // 清除第三个标志
    counter &= ~4;
    flag3 = (counter & 4) == 4;
    cout << "flag3: "<< flag3<< endl;

    return 0;
}