如何在7天的一周内分组时间戳？

import datetime

# 获取需要分组的时间戳列表
timestamps = [1627836000, 1627922400, 1628008800, 1628095200, 1628181600, 1628268000, 1628354400]

# 定义星期几与分组的映射关系
weekday_mapping = {
    0: "星期一",
    1: "星期二",
    2: "星期三",
    3: "星期四",
    4: "星期五",
    5: "星期六",
    6: "星期日"
}

# 定义分组结果的字典
groups = {}

# 遍历时间戳列表
for timestamp in timestamps:
    # 将时间戳转换为日期格式
    date = datetime.datetime.fromtimestamp(timestamp)
    # 获取星期几
    weekday = date.weekday()
    # 根据星期几将时间戳分组
    if weekday in groups:
        groups[weekday].append(timestamp)
    else:
        groups[weekday] = [timestamp]

# 打印分组结果
for weekday, group in groups.items():
    weekday_name = weekday_mapping[weekday]
    print(weekday_name + "的时间戳分组：")
    for timestamp in group:
        print(datetime.datetime.fromtimestamp(timestamp))